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CHAPTER 10. One-Sample Tests of Hypotheses. SOLVED PROBLEMS. Problem 10-1. Problem 10-1(Contd.). Decision rule based on p- value : If p- value greater than , fail to reject H 0 Or If p- value less than , reject H 0 P 1 value =.2(.5000-.3849) = .2302 which is > .05
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CHAPTER 10 One-Sample Tests of Hypotheses SOLVED PROBLEMS Texas A&M - Commerce
Problem 10-1 Texas A&M - Commerce
Problem 10-1(Contd.) Decision rule based on p- value: If p- value greater than , fail to reject H0 Or If p- value less than , reject H0 P1 value =.2(.5000-.3849) = .2302 which is > .05 Therefore fail to reject H0 Texas A&M - Commerce
Problem 10-1 (Cont.) .3849 .1151 .025 .025 z -1.96 1.96 z = -1.2 .5000 - .3849 = .1151 p- Value = .1151 x 2 = .2302 Texas A&M - Commerce
Problem 10-2 Texas A&M - Commerce
Problem 10-2 (Cont.) .48 .02 Texas A&M - Commerce
Problem 10-5 Texas A&M - Commerce
Problem 10-5 (Cont.) .2549 .025 .025 m=60,000 -1.96 -.69 +1.96 .5000-.2549 = .2451 p- value = .2451x2=.4902 Texas A&M - Commerce
Problem 10-6 Texas A&M - Commerce
Problem 10-6 (Cont.) .4616 .05 Z = -1.77 Z = 1.645 .0384 _ m = 3.0 Texas A&M - Commerce
Problem 10-6 (Cont.) Accept .45 Reject .05 -1.768 -1.645 Texas A&M - Commerce
Problem 10-7 Texas A&M - Commerce
Problem 10-7 (cont.) .45 .05 z -7.2 -1.645 Texas A&M - Commerce
Problem 10-8 Texas A&M - Commerce
Problem 10-8 (Cont.) Area of acceptance Area of rejection(0.057) = 80 2.33 z = 8.856 Texas A&M - Commerce
Problem 10-9 Texas A&M - Commerce
Problem 10-9 (Cont.) m=10 1.833 2.108 t Texas A&M - Commerce
Problem 10-10 Texas A&M - Commerce
Problem 10-10 (Cont.) t -3.106 3.106 4.0415 Texas A&M - Commerce
Problem 10-11 Texas A&M - Commerce
Problem 10-12 Texas A&M - Commerce
Problem 10-13 Texas A&M - Commerce
Problem 10-18 Texas A&M - Commerce
Problem 10-19 Texas A&M - Commerce
Problem 10-20 Texas A&M - Commerce
Problem 10-21 Texas A&M - Commerce
Problem 10-22 Texas A&M - Commerce
Problem 10-23 Texas A&M - Commerce
Problem 10-25 6. Stat. Dec: Reject H0 Texas A&M - Commerce
Problem 10-32 Texas A&M - Commerce
Problem 10-35 Texas A&M - Commerce
Problem 10-35 (Cont.) z of 2.366 = .4904 .05 m = 2.50 1.645 2.366z p-value = .5000 - .4904 = .0096 Texas A&M - Commerce
Problem 10-36 Texas A&M - Commerce
Problem 10-36(contd.) .4192 .05 -1.645 -1.40 P-value = .5000 - .4192 = .0808 , p-value>,fail to reject Ho Texas A&M - Commerce
Problem 10-52 Texas A&M - Commerce
Problem 10-54 Texas A&M - Commerce
Problem 10-54 (cont.) Accept Reject .05 z =.10 1.89 Critical Value Z =1.645 Texas A&M - Commerce