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12-2. Arcs and Chords. Holt McDougal Geometry. Holt Geometry. Learning Targets. I will apply properties of arcs and chords. Vocabulary. central angle semicircle arc adjacent arcs minor arc congruent arcs major arc.
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12-2 Arcs and Chords Holt McDougal Geometry Holt Geometry
Learning Targets I will apply properties of arcs and chords.
Vocabulary central angle semicircle arc adjacent arcs minor arc congruent arcs major arc
A central angleis an angle whose vertex is the center of a circle. An arcis an unbroken part of a circle consisting of two points called the endpoints and all the points on the circle between them.
Writing Math Minor arcs are named by the two endpoints of the arc. Major arcs and semicircles must be named by three points, with the endpoints being the first and third points named.
mKLF = 360° – mKJF mKLF = 360° – 126° Example 1: Data Application The circle graph shows the types of grass planted in the yards of one neighborhood. Find mKLF. mKJF = 0.35(360) = 126 = 234
b. mAHB Check It Out! Example 1 Use the graph to find each of the following. a. mFMC mFMC = 0.30(360) = 108 Central is 30% of the . = 360° – mAMB = 0.10(360) c. mEMD mAHB =360° –0.25(360) = 36 = 270 Central is 10% of the .
Adjacent arcs are arcs of the same circle that intersect at exactly one point. RS and ST are adjacent arcs.
Find mBD. mBC = 97.4 mCD = 30.6 mBD = mBC + mCD Example 2: Using the Arc Addition Postulate Vert. s Thm. mCFD = 180 – (97.4 + 52) = 30.6 ∆Sum Thm. mCFD = 30.6 Arc Add. Post. = 97.4 + 30.6 Substitute. Simplify. = 128
mJNL Check It Out! Example 2a Find each measure. 180° + 40° = 220°
mLJN mLJN = 360° – (40 + 25)° Check It Out! Example 2b Find each measure. = 295°
Within a circle or congruent circles, congruent arcs are two arcs that have the same measure. In the figure STUV.
TV WS. Find mWS. TV WS mTV = mWS mWS = 7(11) + 11 Example 3A: Applying Congruent Angles, Arcs, and Chords chords have arcs. Def. of arcs 9n – 11 = 7n + 11 Substitute the given measures. 2n = 22 Subtract 7n and add 11 to both sides. n = 11 Divide both sides by 2. Substitute 11 for n. = 88° Simplify.
GD NM GD NM Example 3B: Applying Congruent Angles, Arcs, and Chords C J, andmGCD mNJM. Find NM. GCD NJM arcs have chords. GD = NM Def. of chords
Example 3B Continued C J, andmGCD mNJM. Find NM. 14t – 26 = 5t + 1 9t = 27 t = 3 NM = 5(3) + 1 = 16
PT bisects RPS. Find RT. mRT mTS Check It Out! Example 3a RPT SPT RT = TS 6x = 20 – 4x 10x = 20 x = 2 RT = 6(2) RT = 12
mCD = mEF mCD = 100 Check It Out! Example 3b Find each measure. A B, and CD EF. Find mCD. 25y = (30y – 20) 20 = 5y 4 = y CD = 25(4)
Step 1 Draw radius RN. Example 4: Using Radii and Chords Find NP. RN = 17 Step 2 Use the Pythagorean Theorem. SN2 + RS2 = RN2 SN2 + 82 = 172 SN2 = 225 SN= 15 Step 3 Find NP. NP= 2(15) = 30
HOMEWORK: Pg 806, #5 – 18.