1 / 8

Introducing…. Section 5.5 Vocabulary

Learn about point-slope form, a method to represent a line using a single point and its slope. Discover how to write equations for lines using this form and practice applying it to different examples.

dbabb
Download Presentation

Introducing…. Section 5.5 Vocabulary

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Introducing…. Section 5.5 Vocabulary Point-Slope form y – y1 = m (x – x1) • another way to show a line • use when you only have one point and the slope • m = slope, (x1, y1) = a point

  2. Notes: Lesson 5-5 Objective: Write equations for lines using point-slope form

  3. Linear Equations: So far, we know: 1. Standard form Ax + By = C x + 2y = 4 2. Slope-intercept form y = m x + b y = - ½ x + 2 m = slope b = y-intercept

  4. 3. Point – Slope Form y – y1 = m (x – x1) (x1, y1) = a given point m= slope This is easy to use if you know a point and the slope

  5. Example 1: Write an equation for the line with a slope of -3 passing through (2, 4) Given: ( , ) m = 2 2 4 4 -3 -3 1. Write y – y1 = m (x – x1) 2. Substitute y – (x – ) = 3. Solve for y y – 4 = -3x + 6 +4 +4 y = -3x + 10

  6. Example 2: Write an equation for the line with a slope of ¾ passing through (-8, 1) Given: ( , ) m = -8 -8 1 1 ¾ ¾ 1. Write y – y1 = m (x – x1) 2. Substitute y – (x – ) = 3. Solve for y y – 1 = ¼ x + 6 +1 +1 y = ¼ x + 7

  7. Your turn. Leave each equation in slope-intercept form: 1. (1, -6) m = -1 2. (-3, -4) m = 0 y – y1 = m (x – x1) y – y1 = m (x – x1) y – -6 = -1 (x – 1) y – -4 = 0 (x – -3) y + 6 = -1x + 1 y + 4 = 0 -6 -6 -4 -4 y = -1x – 5 y = -4

  8. Homework: Lesson 5-5, page 289 #15-26 all Put all answers into y = mx + b form! Chapter 5 Test: Wednesday Math lab today: Room A203 (north)

More Related