1 / 37

Algebra 1 Predicting Patterns & Examining Experiments

Algebra 1 Predicting Patterns & Examining Experiments. Unit 3: Visualizing the Change Section 6: Here and There. Depreciated. A 4-year old car is currently worth $10,800. The car is known to depreciate by $1200 per year. a) What was the original price for the car when it was new?

dcotter
Download Presentation

Algebra 1 Predicting Patterns & Examining Experiments

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Algebra 1Predicting Patterns & Examining Experiments Unit 3: Visualizing the Change Section 6: Here and There

  2. Depreciated A 4-year old car is currently worth $10,800. The car is known to depreciate by $1200 per year. a) What was the original price for the car when it was new? b) How much will the car be worth in two years? c) When will the car be worth nothing?

  3. Depreciated A 4-year old car is currently worth $10,800. The car is known to depreciate by $1200 per year. a) What was the original price for the car when it was new? b) How much will the car be worth in two years? c) When will the car be worth nothing? Extend the table above to find the answers...

  4. Depreciated A 4-year old car is currently worth $10,800. The car is known to depreciate by $1200 per year. a) What was the original price for the car when it was new? b) How much will the car be worth in two years? c) When will the car be worth nothing? Using point-slope form: slope point on the line

  5. Depreciated A 4-year old car is currently worth $10,800. The car is known to depreciate by $1200 per year. a) What was the original price for the car when it was new? b) How much will the car be worth in two years? c) When will the car be worth nothing? Using point-slope form: or changing that to slope-int.:

  6. Depreciated A 4-year old car is currently worth $10,800. The car is known to depreciate by $1200 per year. a) What was the original price for the car when it was new? b) How much will the car be worth in two years? c) When will the car be worth nothing? or

  7. Depreciated A 4-year old car is currently worth $10,800. The car is known to depreciate by $1200 per year. a) What was the original price for the car when it was new? b) How much will the car be worth in two years? c) When will the car be worth nothing? or

  8. Depreciated A 4-year old car is currently worth $10,800. The car is known to depreciate by $1200 per year. a) What was the original price for the car when it was new? b) How much will the car be worth in two years? c) When will the car be worth nothing? or

  9. Depreciated A 4-year old car is currently worth $10,800. The car is known to depreciate by $1200 per year. a) What was the original price for the car when it was new? b) How much will the car be worth in two years? c) When will the car be worth nothing? or

  10. Depreciated A 4-year old car is currently worth $10,800. The car is known to depreciate by $1200 per year. a) What was the original price for the car when it was new? b) How much will the car be worth in two years? c) When will the car be worth nothing?

  11. Depreciated A 4-year old car is currently worth $10,800. The car is known to depreciate by $1200 per year. a) What was the original price for the car when it was new? b) How much will the car be worth in two years? c) When will the car be worth nothing?

  12. Depreciated A 4-year old car is currently worth $10,800. The car is known to depreciate by $1200 per year. a) What was the original price for the car when it was new? b) How much will the car be worth in two years? c) When will the car be worth nothing?

  13. Depreciated A 4-year old car is currently worth $10,800. The car is known to depreciate by $1200 per year. a) What was the original price for the car when it was new? b) How much will the car be worth in two years? c) When will the car be worth nothing?

  14. Depreciated A 4-year old car is currently worth $10,800. The car is known to depreciate by $1200 per year. a) What was the original price for the car when it was new? b) How much will the car be worth in two years? c) When will the car be worth nothing?

  15. Depreciated A 4-year old car is currently worth $10,800. The car is known to depreciate by $1200 per year. a) What was the original price for the car when it was new? b) How much will the car be worth in two years? c) When will the car be worth nothing?

  16. Depreciated A 4-year old car is currently worth $10,800. The car is known to depreciate by $1200 per year. a) What was the original price for the car when it was new? b) How much will the car be worth in two years? c) When will the car be worth nothing?

  17. Depreciated A 4-year old car is currently worth $10,800. The car is known to depreciate by $1200 per year. a) What was the original price for the car when it was new? b) How much will the car be worth in two years? c) When will the car be worth nothing?

  18. Depreciated A 4-year old car is currently worth $10,800. The car is known to depreciate by $1200 per year. a) What was the original price for the car when it was new? Original price was $15,600. b) How much will the car be worth in two years? In two years, value will be $8400. c) When will the car be worth nothing? ... in 13 years.

  19. What is the equation of the line that contains the points ( -5 , 2 ) and ( 3 , 6 ) ?

  20. What is the equation of the line that contains the points ( -5 , 2 ) and ( 3 , 6 ) ? Plan to get equation 1) find slope 2) use point-slope form

  21. What is the equation of the line that contains the points ( -5 , 2 ) and ( 3 , 6 ) ? Plan to get equation 1) find slope 2) use point-slope form But wait, why not just find the slope and plug it into point-slope form all in one step?

  22. What is the equation of the line that contains the points ( -5 , 2 ) and ( 3 , 6 ) ? Plan to get equation 1) find slope 2) use point-slope form New Plan to get eqn: Use two-point form:

  23. What is the equation of the line that contains the points ( -5 , 2 ) and ( 3 , 6 ) ? New Plan to get eqn: Use two-point form:

  24. What will the population of Vermont be in 2010?

  25. What will the population of Vermont be in 2010? +58,446 +63,129 +53,308 +44,926

  26. What will the population of Vermont be in 2010? not linear! +58,446 +63,129 +53,308 +44,926

  27. What will the population of Vermont be in 2010? +58,446 +63,129 +53,308 +44,926

  28. What will the population of Vermont be in 2010? +58,446 +63,129 not linear... but close! +53,308 +44,926

  29. What will the population of Vermont be in 2010? +58,446 +63,129 +53,308 +44,926 We are going to use the average rate of change over the 40-years of data we have in order to estimate the population in 2010.

  30. What will the population of Vermont be in 2010? +40 +220,009

  31. What will the population of Vermont be in 2010?

  32. What will the population of Vermont be in 2010? Our prediction is that the population of Vermont will be 664,892 in 2010.

  33. The population of Vermont in 2006 was 623,908. Based upon this information, how accurate is the equation we have developed?

  34. The population of Vermont in 2006 was 623,908. Based upon this information, how accurate is the equation we have developed?

  35. The population of Vermont in 2006 was 623,908. Based upon this information, how accurate is the equation we have developed?

  36. The population of Vermont in 2006 was 623,908. Based upon this information, how accurate is the equation we have developed? Our equation overestimates the 2006 population by 18,983 people. Therefore, the 2010 value we previously found is likely high. Our slope of 5500 people/year tells us that our over-estimation puts us about three years worth above the actual.

  37. Disclaimer • All photos contained are used undercreative commons rights. • Citroen C2 VTR 002 by someonessomewhereslife • http://www.flickr.com/photos/someonesomewhereslife/2350463819/ • Welcome to Vermont by phillacombe • http://www.flickr.com/photos/phillacombe/3711079357/

More Related