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Continuous Probability Distributions (The Normal Distribution-II). QSCI 381 – Lecture 17 (Larson and Farber, Sect 5.4-5.5). Finding z-scores-I. Yesterday we addressed the question: What is the probability that a normal random variable, X , would lie between x 1 and x 2 .
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Continuous Probability Distributions (The Normal Distribution-II) QSCI 381 – Lecture 17 (Larson and Farber, Sect 5.4-5.5)
Finding z-scores-I • Yesterday we addressed the question: • What is the probability that a normal random variable, X, would lie between x1 and x2. • To address this question we found the probabilities P[X x1] and P[X x2] and calculated the difference between them. • Today we are going to address the inverse of this question. • Find the z-score which corresponds to a cumulative area under the standard normal curve of p.
Finding z-scores-II Area=0.8 X? What value of x corresponds to an area of 0.8?
Finding z-scores-II • We can use a table of z-scores or the EXCEL function NORMINV: • NORMINV(p,,) • Once you have a z-score for a given cumulative probability, you can find x for any and using the formula:
Example-I • The length distribution of the catch of a given species is normally distributed with mean 500 mm and standard deviation 30 mm. • Find the maximum length of the smallest 5%, 50% and 75% of the catch.
Example-II -1.64 0 0.674 Find the z-score for each level (5%, 50% and 75%)
Example-III • We now apply the formula: so the maximum lengths are 450.7, 500 and 520.2 mm.
Sampling and Sampling Distributions-I • So far we have been working on the assumption that we know the values for and . This is rarely the case and generally we need to estimate these quantities from a sample. The relationship between the population mean and the mean of a sample taken from the population is therefore of interest.
Sampling and Sampling Distributions-II sampling distribution • A is the probability distribution of a sample statistic that is formed when samples of size n are repeatedly taken from a population. If the sample statistic is the sample mean, then the distribution is the sampling distribution of sample means.
Sampling and Sampling Distributions-III(Example) • Consider a population of fish in a lake. The mean and standard deviation of the lengths of these fish are 300 mm and 50 mm respectively. • We now take 100 random samples where each sample is of size 10, 20, or 100. What can we learn about the population mean?
Sampling and Sampling Distributions-IV(Example) N=10 N=20 N=100
Properties of the Sampling Distribution for the Sample Mean • The mean of the sample means is equal to the population mean: • The standard deviation of the sample means is equal to the population standard deviation divided by the square root of n. • is often called the standard deviation of the mean
The Central Limit Theorem • If samples of size n (where n 30) are drawn from any population with a mean and a standard deviation , the sampling distribution of sample means approximates a normal distribution. The greater the sample size, the better the approximation. • If the population is itself normally distributed, the sampling distribution of the sample means is normally distributed for any sample size.
Probabilities and the Central Limit Theorem • The distribution of the heights of trees are not normally distributed. We sample 100 (of many) trees in a (very large) stand and calculate sample mean and sample standard deviation to be 12.5m and 2.3m respectively. • What is the standard deviation of the mean? • What is the probability that the population mean is less than 12m?