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Why is water more stable as a solid below 0 o C but as a liquid above it?. What controls why only some things happen?. Energy is neither created or destroyed during chemical or physical changes, but it is transformed from one form to another. E universe = 0. TYPES of ENERGY
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Why is water more stable as a solid below 0 oC but as a liquid above it?
Energy is neither created or destroyed during chemical or physical changes, but it is transformed from one form to another.Euniverse = 0
TYPES of ENERGY Kinetic Potential Mechanical Gravitational Thermal Electrostatic Electrical Chemical Radiant
Dropping a rock? • Gravitational Mechanical • Gravitational Thermal • Gravitational Gravitational
Using a flashlight? • Thermal Radiant • Chemical Thermal • Chemical Radiant • Electrostatic Radiant
One turn of a giant windmill produces 0.26 kWh of electricity. How many kJ is this?
SYSTEM and SURROUNDINGS System: The thing under study Surroundings: Everything else in the universe Energy transfer between system and surroundings: Endo: heat added to system Exo: heat released by system
Dissolution of KNO3 HCl(aq) + NaOH(aq) H2O(l) + NaCl(aq)
HEAT: What happens to thermal (heat) energy? Three possibilities: • Warms another object • Causes a change of state • Is used in an endothermic reaction
Temperature Changes from Heat Exchange Bill, go to the next slide. You know you want to. Example 1: 5 g wood at 0 oC + 5 g wood at 100 oC Example 2: 10 g wood at 0 oC + 5 g wood at 100 oC Example 3: 5 g copper at 0 oC + 5 g copper at 100 oC Example 4: 5 g wood at 0 oC + 5 g copper at 100 oC Clicker Choices: 1: 0 oC 2: 33 oC 3: 50 oC 4. 67 oC 5: 100 oC 6: other
Temperature Changes from Heat Exchange 5 g wood at 0 oC + 5 g wood at 100 oC • 0 oC • 33 oC • 50 oC • 67 oC • 100 oC • other
Temperature Changes from Heat Exchange 10 g wood at 0 oC + 5 g wood at 100 oC • 0 oC • 33 oC • 50 oC • 67 oC • 100 oC • other
Temperature Changes from Heat Exchange 5 g copper at 0 oC + 5 g copper at 100 oC • 0 oC • 33 oC • 50 oC • 67 oC • 100 oC • other
Temperature Changes from Heat Exchange 5 g wood at 0 oC + 5 g copper at 100 oC • 0 oC • 33 oC • 50 oC • 67 oC • 100 oC • other
Conclusion I: What happens to thermal (heat) energy? When objects of different temperature meet: • Warmer object cools • Cooler object warms • Thermal energy is transferred • qwarmer = -qcooler
Conclusion II: What controls the magnitude of an object’s temperature change?
Quantitative: Calculating Heat Exchange: Specific Heat Capacity
Calculate the specific heat capacity of copper: Calculate the specific heat capacity of wood:
Which has the smallest specific heat capacity? • Wood • Copper • Silver • Water
Specific Heat Capacity The energy required to heat one gram of a substance by 1 oC. Usefulness: #J transferred = S.H. x #g x T How much energy is used to heat 250 g water from 17 oC to 100 oC?
What happens to thermal (heat) energy? When objects of different temperature meet: • Warmer object cools • Cooler object warms • Thermal energy is transferred • qwarmer = -qcooler specific heat x mass x T = specific heat x mass x T warmer object cooler object
Conceptually Easy Example with Annoying Algebra: If we mix 250 g H2O at 95 oC with 50 g H2O at 5 oC, what will the final temperature be?
Thermal Energy and Phase Changes First: What happens?
Thermal Energy and Phase Changes First: What happens?
Thermal Energy and Phase Changes First: What happens?
But what’s really happening? • Warming: • Molecules move more rapidly • Kinetic Energy increases • Temperature increases • Melting/Boiling: • Molecules do NOT move more rapidly • Temperature remains constant • Intermolecular bonds are broken • Chemical potential energy (enthalpy) increases
Energy and Phase Changes: Quantitative Treatment Melting: Heat of Fusion (DHfus) for Water: 333 J/g Boiling: Heat of Vaporization(DHvap) for Water: 2256 J/g
Total Quantitative Analysis Convert 40.0 g of ice at –30 oC to steam at 125 oC Warm ice: (Specific heat = 2.06 J/g-oC) Melt ice: Warm water (s.h. = 4.18 J/g-oC)
Total Quantitative Analysis Convert 40.0 g of ice at –30 oC to steam at 125 oC Boil water: Warm steam (s.h. = 1.92 J/g-oC)
Enthalpy Change and Chemical Reactions DH = energy needed to break bonds – energy released forming bondsExample: formation of water: DH = ?
Enthalpy Change and Chemical Reactions DH is usually more complicated, due to solvent and solid interactions. So, we measure DH experimentally. Calorimetry Run reaction in a way that the heat exchanged can be measured. Use a “calorimeter.”
Calorimetry Experiment N2H4 + 3 O2 2 NO2 + 2 H2O Energy released = E absorbed by water + E absorbed by calorimeter Ewater = Ecalorimeter = Total E = H = energy/moles = 0.500 g N2H4 600 g water 420 J/oC
Hess’s Law If reactions can be “added” so can their H values.