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Gibbs Phase Rule. The number of variables which are required to describe the state of a system: p+f=c+2 f=c-p+2 Where p=# of phases, c= # of components, f= degrees of freedom
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Gibbs Phase Rule • The number of variables which are required to describe the state of a system: • p+f=c+2 f=c-p+2 • Where p=# of phases, c= # of components, f= degrees of freedom • The degrees of freedom correspond to the number of intensive variables that can be changed without changing the number of phases in the system
Variance and f • f=c-p+2 • Consider a one component (unary) diagram • If considering presence of 1 phase (the liquid, solid, OR gas) it is divariant • 2 phases = univariant • 3 phases = invariant
Free Energy • Gibbs realized that for a reaction, a certain amount of energy goes to an increase in entropy of a system. • G = H –TS or DG0R = DH0R – TDS0R • Gibbs Free Energy (G) is a state variable, measured in KJ/mol • Tabulated values of DG0R are in Appendix
Now, how does free energy change with T and P? • From DG=DH-TDS: • T and P changes affect free energy and can drive reactions!!
Volume Changes (Equation of State) For Minerals: Volume is related to energy changes: Mineral volume changes as a function of T: a, coefficient of thermal expansion Mineral volume changes as a function of P: b, coefficient of isothermal expansion
Volume Changes (Equation of State) • Gases and liquids undergo significant volume changes with T and P changes • Number of empirically based EOS solns.. • For metamorphic environments: • Redlich and Kwong equation: • V-bar denotes a molar quatity, aRw and bRK are constants
Phase Relations • Rule: At equilibrium, reactants and products have the same Gibbs Energy • For 2+ things at equilibrium, can investigate the P-T relationships different minerals change with T-P differently… • For DGR = DSRdT + DVRdP, at equilibrium, DG=0, rearranging: Clausius-Clapeyron equation Remember that a line on a phase diagram describes equilibrium, DGR=0!!
V = Vº(1-bDP) DSR change with T or P? DV for solids stays nearly constant as P, T change, DV for liquids and gases DOES NOT • Solid-solid reactions linear S and V nearly constant, DS/DV constant + slope in diagram • For metamorphic reactions involving liquids or gases, volume changes are significant, DV terms large and a function of T and P (and often complex functions) – slope is not linear and can change sign (change slope + to –)
Example – Diamond-graphite • To get C from graphite to diamond at 25ºC requires 1600 MPa of pressure, let’s calculate what P it requires at 1000ºC:
Phase diagram • Need to represent how mineral reactions at equilibrium vary with P and T