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Recrystallization. Impure benzoic acid. Benzoic acid after recrystallization. Benzoic Acid. Purification of Organic Compounds. Solids: Recrystallization. Liquids: Distillation. Solids and Liquids: Gas or liquid chromotography. Types of impurities. Soluble Insoluble
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Recrystallization Impure benzoic acid Benzoic acid after recrystallization
Purification of Organic Compounds Solids:Recrystallization Liquids: Distillation Solids and Liquids: Gas or liquid chromotography
Types of impurities Soluble Insoluble Partly Soluble
Dissolve sample in hot solvent Compound crystallizes upon cooling
Add water and heat until all soluble material dissolves Insoluble material is removed by filtration
Use GLASS funnel. To avoid crystallization in the funnel: Put flask on hot plate.
Hot solution after filtration: Cool Seed Scratch
Crystals form in the warm solution Next: Cool, filter, wash, dry, weigh, mp
.. Buchner funnel Heavy-walled tubing Filter flask Vacuum
Filter paper .. Put filter paper in Buchner funnel
Filter, Wash Filter and wash with cold solvent
Summary Purified benzoic acid Insoluble impurities Soluble impurities
Solubility Example Solubility g/100 mL Compound 25o 100o A I1 I2 1.0 1.5 0.0 80 50 0.0
Solubility g/100 mL Compound 25o 100o Example A I1 I2 1.0 1.5 0.0 80 50 0.0 A = 10 g I1 = 1.0 g I2 = 1.0 g Total = 12.0 g 100 mL water at 1000 A I1 I2 dissolves dissolves insoluble
Solubility g/100 mL Compound 25o 100o Example A I1 I2 1.0 1.5 0.0 80 50 0.0 A = 10 g I1 = 1.0 g I2 = 1.0 g Total = 12.0 g Cool to 25o 100 mL water at 1000 A dissolves I1 dissolves I2 insoluble A I1 9.0 g crystallize 0 g crystallize Yield = 100 * 9.0/12.0 = 75%
Solubility g/100 mL Compound 25o 100o Example A I1 I2 1.0 1.5 0.0 80 50 0.0 A = 10 g I1 = 1.0 g I2 = 1.0 g Total = 12.0 g 50 ml of water at 1000 A I1 I2 dissolves dissolves insoluble
Solubility g/100 mL Compound 25o 100o Example A I1 I2 1.0 1.5 0.0 80 50 0.0 A = 10 g I1 = 1.0 g I2 = 1.0 g Total = 12.0 g Cool to 25o 50 mL water at 1000 A dissolves I1 dissolves I2 insoluble A I1 9.5 g crystallize 0.25 g crystallize Yield = 100 * 9.75/12.0 = 81% NOT PURE!
What volume of solvent is needed to give the maximum yield of pure A? Example Solubility of I1 = 1.5 g/100 mL 1.5 g 100 mL 1.0 g x mL = X = (100 mL * 1.0 g)/1.5 g = 67 mL
What is the yield of pure A from 67 mL solvent? Example Solubility of A = 1.0 g/100 mL 1.0 g 100 mL X g 67 mL = X = (67 mL x 1.0 g) / 100 mL = 0.67 g Yield = 10.0 g - 0.67 g = 9.33 g % yield = 100 * 9.33 / 12 = 78%
Second Crop Boil off some solvent Cool, filter, wash, dry, weigh, mp
Recrystallization Solvents • Does not react with compound • Large temperature coefficient of solution • Low boiling point
Mixed Solvents • Ethanol – Water • Ether Pentane