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Solving Multi-Step Equations

2 c + 3 c + 2 = 12 Commutative Property. 5 c + 2 = 12 Combine like terms. 5 c + 2 – 2 = 12 – 2 Subtract 2 from each side. 5 c = 10 Simplify. =. Divide each side by 5. 5 c 5. 10 5. c = 2 Simplify. COURSE 3 LESSON 2-4. Solving Multi-Step Equations.

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Solving Multi-Step Equations

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  1. 2c + 3c + 2 = 12 Commutative Property 5c + 2 = 12 Combine like terms. 5c + 2 – 2 = 12 – 2Subtract 2 from each side. 5c = 10 Simplify. = Divide each side by 5. 5c 5 10 5 c = 2 Simplify. COURSE 3 LESSON 2-4 Solving Multi-Step Equations Solve 2c + 2 + 3c = 12. 2c + 2 + 3c = 12 2-4

  2. 2(2) + 2 + 3(2) 12 Substitute 2 for c. 12 = 12 The solution checks. COURSE 3 LESSON 2-4 Solving Multi-Step Equations (continued) Check 2c + 2 + 3c = 12 2-4

  3. Words 8 cheerleaders • (28 boxes + = 424 boxes Let x = the number of additional boxes. Equation 8 • (28 + x) = 424 additional boxes COURSE 3 LESSON 2-4 Solving Multi-Step Equations Eight cheerleaders set a goal of selling 424 boxes of cards to raise money. After two weeks, each cheerleader has sold 28 boxes. Write and solve an equation to find out how many more boxes each cheerleader must sell. 8(28 + x) = 424 2-4

  4. 224 + 8x = 424 Distributive Property 224 – 224 + 8x = 424 – 224Subtract 224 from each side. 8x = 200 Simplify. 8x 8 200 8 = Divide each side by 8. x = 25 Simplify. COURSE 3 LESSON 2-4 Solving Multi-Step Equations (continued) Each cheerleader must sell 25 more boxes. Check for Reasonableness Round 8 to 10 and 28 to 20. The cheerleaders sold about 10 • 20, or 200 boxes. This means each cheerleader must sell about 22 more boxes. 25 is close to 22. The answer is reasonable. 2-4

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