1 / 3

Instruction Memory

1. 0. Registers. Read reg. num A. Read reg num A. Read reg data A. Read reg num B. Write reg num. Read reg data B. Write reg data. 0. 1. Problem HW8-2 – Name each identified portion of the registers and indicate # of bits. Branch Target [32]. PCSrc. 4. Branch. PC+4. Result.

donovan-merritt
Download Presentation

Instruction Memory

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. 1 0 Registers Read reg. num A Read reg num A Read reg data A Read reg num B Write reg num Read reg data B Write reg data 0 1 Problem HW8-2 –Name each identified portion of the registers and indicate # of bits Branch Target [32] PCSrc 4 Branch PC+4 Result Result Add MemToReg Sh.Left2 RegWrite Add MemWrite Rs:[25-21] Read address Rt:[20-16] Data Memory ALUSrc Read address PC Zero Read data 1 Instruction [31-0] Write address Result InstructionMemory 0 0 Write data 1 Imm:[15-0] MemRead ALUcontrol 16 32 signextend Rt:[20-16] Rd:[15-11] ALUOp RegDest

  2. Problem HW8-3 – Give value for each register portion indicated 1 0 Registers Read reg. num A Read reg num A Read reg data A Read reg num B Write reg num Read reg data B Write reg data 0 1 LW $10,20($1)(from mem[31]) Add $14,$8,$9 Or $13, $6, $7 And $12,$4,$5 Sub $11,$2,$3 1100 1100 E 000 PCSrc Control 000 000 M M ‘OR’=0 10 10 11 10 W W W 4 0 Branch PC+4 Result Result Add Sh.Left2 Add RegWrite 1 0 MemToReg MemWrite 6 Read address 1 7 Data Memory Read address PC ALUSrc Zero Read data 1 Instruction [31-0] 0 Write address Result InstructionMemory 0 0 Write data 1 • Initial Conditions (before any instructions are executed): • PC=50010 (address ofLW instruction) • Each register has the value 10+register number. For example $5 = 15. • Memory locations have the value 100010+byte address of the word. For example Mem[8]=1008. Imm:[15-0] ALUcontrol 16 32 signextend 0 MemRead Rt:[20-16] 10 11 10 12 13 ALUOp RegDest 1 Execute stage signal ordering: RegDest, ALUOp1, ALUOp0, ALUSrcMemory stage signal ordering: Branch, MemRead, MemwriteWriteback stage signal ordering: RegWrite, MemToReg

  3. Problem HW8-4 – Find out all you can about the five instructions in the pipeline 1 0 Registers Read reg. num A Read reg num A Read reg data A Read reg num B Write reg num Read reg data B Write reg data 0 1 Execute stage signal ordering: RegDest, ALUOp1, ALUOp0, ALUSrcMemory stage signal ordering: Branch, MemRead, MemwriteWriteback stage signal ordering: RegWrite, MemToReg 0001 1100 E 100 PCSrc Control 001 000 M M 10 00 11 00 W W W 4 1 Branch Result Result Add Sh.Left2 Add RegWrite 1 0 MemToReg MemWrite 10 Read address 15 1 11 Data Memory Read address PC ALUSrc Zero Read data 1 Instruction [31-0] 1 Write address Result 15 16 InstructionMemory 0 0 Write data 1 • Initial Conditions (before any instructions are executed): • PC=50010 (address ofrightmost instruction) • Each register has the value 10+register number. For example $5 = 15. • Memory locations have the value 100010+byte address of the word. For example Mem[8]=1008. ALUcontrol 16 16 32 signextend 2090 0 MemRead 6 11 31 15 0 1 00 ALUOp RegDest 0

More Related