1 / 23

Geometry Academic

Geometry Academic. UNIT QUESTION: What patterns can I find in right triangles? Standard: MM2G1, MM2G2 Today ’ s Question: How do we solve 45°-45°-90° right triangles? Standard: MM2G1.b. Special Right Triangles. You will be able to find the lengths of sides of special right triangles.

dora-nunez
Download Presentation

Geometry Academic

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Geometry Academic UNIT QUESTION: What patterns can I find in right triangles? Standard: MM2G1, MM2G2 Today’s Question: How do we solve 45°-45°-90° right triangles? Standard: MM2G1.b

  2. Special Right Triangles You will be able to find the lengths of sides of special right triangles 45-45-90 And 30-60-90

  3. 45-45-90

  4. We will use a reference triangle to set up a proportion then solve. In a 45-45-90 triangle… LEGS ARE THE SAME LENGTH

  5. 45-45-90 Right Triangle 1 1 This is our reference triangle for the 45-45-90.

  6. 45-45-90 Right Triangle x x

  7. Special Right Triangles Leg:Leg:Hypotenuse

  8. EX: 1 Solve for x a√2 x a 3 a 3

  9. EX: 2 Solve for x x a√2 a 5 a 5

  10. EX: 3 Solve for x 45 3 a√2 a x a

  11. Extension Problem The diagonal of a square is 12 inches. Find the area. Round to the nearest tenth. 12 in. Area = 72 in.2

  12. Extension Problem 2 Given a circle with a diameter of 12 inches, find the length of the hypotenuse of a right triangle with the right angle at the center. X 12 inches

  13. Real Life Problem

  14. 30-60-90

  15. We will use a reference triangle to set up a proportion then solve. 30-60-90 Right Triangle 60 2 1 30 This is our reference triangle for the 30-60-90 triangle.

  16. Special Right Triangles Short Leg:Long Leg:Hypotenuse

  17. Ex: 1 Solve for x and y. 60 8 2a x a 30 y a√3

  18. Solve for x and y Ex: 2 y a√3 30 x a 2a 24 60

  19. Ex: 3 Solve for x and y. 30 2a 14 y a√3 60 x a y = 7√3 x = 7

  20. Ex: 4 Solve for x and y a x a√3 60 30 y 2a y = 10 x = 5

  21. Extension Problem The altitude of an equilateral triangle is 8 inches. Find the perimeter of the triangle. 30° 2a a√3 8 60° a a = 4.168 in., so 2a = 9.238 in. Perimeter = 27.71 inches

  22. Real Life Problem D A 30° 30° C B 90 feet. • A person is standing at point A cheering on his favorite team. Round to nearest tenth. • Find the height CD of the bleachers. • Find the height of the fan at Point A from the ground. • Find the distance AB that the fan is from the field at B. 52.0 feet 39.0 feet 77.9 feet

  23. Homework Page 557, and 562

More Related