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11.3 – Perimeter and Area of Similar Figures

11.3 – Perimeter and Area of Similar Figures. Find the ratio of the sides, perimeters, and areas of the similar rectangles. 2. 3. 6. 9. 3 2. Ratio of Sides:. Find the ratio of the sides, perimeters, and areas of the similar rectangles. 2. 3. 6. 9. P =. 9 + 3 + 9 + 3. P =.

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11.3 – Perimeter and Area of Similar Figures

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  1. 11.3 – Perimeter and Area of Similar Figures

  2. Find the ratio of the sides, perimeters, and areas of the similar rectangles. 2 3 6 9 3 2 Ratio of Sides:

  3. Find the ratio of the sides, perimeters, and areas of the similar rectangles. 2 3 6 9 P = 9 + 3 + 9 + 3 P = 6 + 2 + 6 + 2 P = 24u P = 16u 24 16 3 2 = Ratio of Perimeters:

  4. Find the ratio of the sides, perimeters, and areas of the similar rectangles. 2 3 6 9 A = bh A = bh A = (9)(3) A = (6)(2) A = 27u2 A = 12u2 27 12 9 4 = Ratio of Areas:

  5. If two polygons are _____________ with the lengths of corresponding sides in the ratio ___________, then the ratio of their areas is ____________. similar a:b a2:b2 S P A a2 b2 a b a b

  6. The ratio of the areas of two similar figures is given. Write the ratio of the lengths of corresponding sides. Ratio of areas = 4:225 S P A 2 . 15 2 . 15 4 . 225

  7. The ratio of the areas of two similar figures is given. Write the ratio of the lengths of corresponding sides. Ratio of areas = 16:49 S P A 16. 49 4 7 4 7

  8. The ratio of the areas of two similar figures is given. Write the ratio of the lengths of corresponding sides. Ratio of areas = 36:4 S P A 36. 4 6 2 6 2

  9. Use the given area to find XY. S P A 144 36 2 1 12 6 2 1 = 2x = 10 x = 5in

  10. Use the given area to find XY. S P A 4 9 168 378 2 3 2 3 = 2x = 24 x = 12cm

  11. Corresponding lengths in similar figures are given. Find the ratios (shaded to unshaded) of the perimeters and areas. Find the unknown area. S P A 1 . 16 2 8 1 4 1 4 = x = 48ft2

  12. Corresponding lengths in similar figures are given. Find the ratios (shaded to unshaded) of the perimeters and areas. Find the unknown area. S P A 9 . 25 9 15 3 5 3 5 = 25x = 2025 x = 81in2

  13. HW Problems #28 S P A 60 90 2 3 2 3 4. 9 = 9x = 80 x = 8.88 B

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