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PHY 2049: Physics II. Coulomb’s law: Two kinds of charges, positive and negative, unlike attract, like repel. Electrons and Protons: q = ± 1.602 x 10 -19 C Current I = dq/dt 1 Amp. = 1 C/s Add forces as vectors. PHY 2049: Physics II. A rule
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PHY 2049: Physics II • Coulomb’s law: • Two kinds of charges, positive and negative, unlike attract, like repel. • Electrons and Protons: q = ± 1.602 x 10-19 C • Current I = dq/dt 1 Amp. = 1 C/s • Add forces as vectors
PHY 2049: Physics II • A rule Try to calculate the force magnitude by ignoring the signs of charges. Then assign the direction by looking at the signs. Never do both (using the charge signs in the calculation of the force and then assign the direction).
PHY 2049: Physics II • q1 = 2Q • q2 = - 2Q • q3 = -4Q E at origin
In Fig. at right, the particles have charges q1 = -q2 = 300 nC and q3 = -q4 = 200 nC, and distance a = 4.0 cm. What is the direction of the force on particle 4? A. B. C. D. [-0.344N, -0.218N], 212.38º Phy 2049: Physics II trial run
3,1,2 PHY 2049: Physics II • Balls are touched and then separated. Rank them by • Charge left • Magnitude of Force before • After • Charge transferred
TALP: Take a look Problem PHY 2049: Physics II • Force on the center charge = 6kq2/d2 • Direction: -x, 180º, d
PHY 2049: Physics II • q1 = q4 = Q; q2 = q3 = q • what is Q/q so that the force on 1 is zero • All charges samesign. There is no solution. • Q and q different sign. There is a possible solution. • Is the answer the same if the force on 3 is to be zero
PHY 2049: Physics II • What is the force on the central chlorine ion? • Suppose that we put in an electron that sits on a cesium site and neutralizes it, which way does the Chlorine move?
Electric Field Force F = qE E = k ∑ rˆ qi/ri2 PHY 2049: Physics II environment Test charge
Electric field lines denote direction • Their density represents magnitude • They do not cross
PHY 2049: Physics II Induction and charge transfer on contact Forces summed as vectors Electric fields
Physics II • Potentials add like numbers