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4 .1 Vector Addition & Subtraction

4 .1 Vector Addition & Subtraction. We will be working on this section from the board. 4 .2 Vector Components Part 1. 4.2 Vector Components Part 1. 1. What is the northerly and easterly component of the velocity below. E. v N = 30sin30 = 15 ms -1. v E = 30cos30

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4 .1 Vector Addition & Subtraction

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  1. 4.1 Vector Addition & Subtraction We will be working on this section from the board

  2. 4.2 Vector Components Part 1

  3. 4.2 Vector Components Part 1 1. What is the northerly and easterly component of the velocity below E vN =30sin30 = 15ms-1 vE =30cos30 = 25.98076ms-1

  4. 4.2 Vector Components Part 1 2. What is the northerly and easterly component of the velocity below vE =– 10sin20 = –3.42020ms-1 E vN =10cos20 = 9.39693ms-1

  5. 4.2 Vector Components Part 1 3. Work out the horizontal and vertical components of the force below: x y Fy =8sin40 = 5.13230N Fx =8cos40 = 6.12836N

  6. 4.2 Vector Components Part 1 4. Work out the horizontal and vertical velocity components of the golfball below: x y vy =35sin60 = 30.31089ms-1 vx =35cos60 = 17.5ms-1

  7. 4.2 Vector Components Part 1 5(a) Work out the weight into the slope and down the slope. x y Wy =20cos20 = 18.79385N W=mg = 20N Wx =20sin20 = 6.84040N

  8. 4.2 Vector Components Part 1 5(b) What is the acceleration down the slope if it is frictionless. x y In x direction a = ? Fnet = 6.84040N m = 2.0kg Fnet = a = a = a= 3.42020 a 3.4 ms-2 Wy =20cos20 = 18.79385N W=mg = 20N Wx =20sin20 = 6.84040N

  9. 4.2 Vector Components Part 1 5(c) What is the normal reaction force on the mass. x N y In y direction N = Wy N = 18.79385N N  19N Wy =20cos20 = 18.79385N W=mg = 20N Wx =20sin20 = 6.84040N

  10. 4.2 Vector Components Part 1 6(a) Work out an expression for the net force down the frictionless slope below. x y Fx =mgsin W=mg Wx =mgsin

  11. 4.2 Vector Components Part 1 6(b) What is the formula for the acceleration of a mass down a frictionless slope? x y In x direction a = ? Fnet = mgsin m = m Fnet = a = a= g sin Fx =mgsin W=mg Wx =mgsin

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