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Homework:

Homework:. Page 512 problems 31, 34, 35. 31. a. CaCO 3 → CaO + CO 2. 31. a. CaCO 3 → CaO + CO 2 ∆ H f (reaction) = 178.3 kJ. 31. b. CH 4 + 2Cl 2 → CCl 4 + 2H 2. 31. b. CH 4 + 2Cl 2 → CCl 4 + 2H 2 ∆H f(reaction) = -53.4 kJ. 31. c. N 2 + 2O 2 → 2NO 2. 31. c.

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Homework:

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  1. Homework: Page 512 problems 31, 34, 35

  2. 31. a. CaCO3→ CaO + CO2

  3. 31. a. CaCO3→ CaO + CO2 ∆Hf(reaction) = 178.3 kJ

  4. 31. b. CH4 + 2Cl2→ CCl4 + 2H2

  5. 31. b. CH4 + 2Cl2→ CCl4 + 2H2 ∆Hf(reaction) = -53.4 kJ

  6. 31. c. N2 + 2O2→ 2NO2

  7. 31. c. N2 + 2O2→ 2NO2 ∆Hf(reaction) = 66.36 kJ

  8. 31. d. 2H2O2→ 2H2O + O2

  9. 31. d. 2H2O2→ 2H2O + O2 ∆Hf(reaction) = -196.1 kJ

  10. 31. e. 4NH3 + 7O2→ 4NO2 + 6H2O

  11. 31. e. 4NH3 + 7O2→ 4NO2 + 6H2O ∆Hf(reaction) = -1397.82 kJ

  12. 34. On the scale of standard enthalpies of formations, how are the elements in their standard states defined?

  13. 35. Low energy is associated with stability. Examine the data in table 16-7. what conclusion can you draw about the stabilities of the compounds listed relative to the elements in their standard states? .

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