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By: Prof. Y. Peter Chiu 10 / 31 / 2010

POM Oct-2010 – Mid-Term Exam. #1 - A 卷 ~ SOLUTION 2 of 2 ~ #12 ~ #20. By: Prof. Y. Peter Chiu 10 / 31 / 2010. #16~#18. #16~20. (#16). (#18). (#17) K = (23*8) / 4.6 = 40. #18. Overall costs = 29(500)+32(250)+280(8) +1000(8) = $32,740

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By: Prof. Y. Peter Chiu 10 / 31 / 2010

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  1. POM Oct-2010 – Mid-Term Exam. #1 - A卷 ~ SOLUTION 2 of 2 ~ #12 ~ #20 By: Prof. Y. Peter Chiu 10 / 31 / 2010

  2. #16~#18 #16~20 (#16) (#18) (#17) K = (23*8) / 4.6 = 40

  3. #18 Overall costs = 29(500)+32(250)+280(8) +1000(8) = $32,740 if adjust costs = 28(500)+30(250)+120(8)+1000(8) = $30,460

  4. #19 40 Overall costs = 7(250)+3040(8)+1000(8) = $ 34,070

  5. Case1 #20 -7.2%

  6. #20 Case2 -23.8%

  7. #20 Case3 -10.2%

  8. #20 Case4 -26.4%

  9. Case5 #20 -24.4%

  10. The End ≒

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