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Explore the concepts of derangements and generating functions in permutations and combinations, along with detailed examples and explanations. Understand how to find derangements, permutations with relative forbidden positions, and utilize generating functions for various scenarios.
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2.Derangements • A derangement of {1,2,…,n} is a permutation i1i2…in of {1,2,…,n} in which no integer is in its natural position: • i11,i22,…,inn. • We denote by Dn the number of derangements of {1,2,…,n}. • Theorem 4.15:For n1,
Proof: Let S={1,2,…,n} and X be the set of all permutations of S. Then |X|=n!. • For j=1,2,…,n, let pj be the property that in a permutation, j is in its natural position. Thus the permutation i1,i2,…,in of S has property pj provided ij=j. A permutation of S is a derangement if and only if it has none of the properties p1,p2,…,pn. • Let Aj denote the set of permutations of S with property pj ( j=1,2,…,n).
Example:(1)Determine the number of permutations of {1,2,3,4,5,6,7,8,9} in which no odd integer is in its natural position and all even integers are in their natural position. • (2) Determine the number of permutations of {1,2,3,4,5,6,7,8,9} in which four integers are in their natural position.
3. Permutations with relative forbidden position • A Permutations of {1,2,…,n} with relative forbidden position is a permutation in which none of the patterns i,i+1(i=1,2,…,n) occurs. We denote by Qn the number of the permutations of {1,2,…,n} with relative forbidden position. • Theorem 4.16:For n1, • Qn=n!-C(n-1,1)(n-1)!+C(n-1,2)(n-2)!-…+(-1)n-1 C(n-1,n-1)1!
Proof: Let S={1,2,…,n} and X be the set of all permutations of S. Then |X|=n!. • j(j+1), pj(1,2,…,n-1) • Aj: pj • Qn=Dn+Dn-1
4.6 Generating functions • 4.6.1 Generating functions • Let S={n1•a1,n2•a2,…,nk•ak}, and n=n1+n2+…+nk=|S|,then the number N of r-combinations of S equals • (1)0 when r>n • (2)1 when r=n • (3) N=C(k+r-1,r) when nir for each i=1,2,…,n. • (4)If r<n, and there is, in general, no simple formula for the number of r-combinations of S. • A solution can be obtained by the inclusion-exclusion principle and technique of generating functions. • 6-combination a1a1a3a3a3a4
xi1xi2…xik= xi1+i2+…+ik=xr • r-combination of S • Definition 1: The generating function for the sequence a0,a1,…,an,… of real numbers is the infinite series f(x)=a0+a1x+a2x2+…+anxn+…, and if only if ai=bi for all i=0,1, …n, …
We can define generating function for finite sequences of real numbers by extending a finite sequences a0,a1,…,an into an infinite sequence by setting an+1=0, an+2=0, and so on. • The generating function f(x) of this infinite sequence {an} is a polynomial of degree n since no terms of the form ajxj, with j>n occur, that is f(x)=a0+a1x+a2x2+…+anxn.
Example: (1)Determine the number of ways in which postage of r cents can be pasted on an envelope using 1 1-cent,1 2-cent, 1 4-cent, 1 8-cent and 1 16-cent stamps. • (2)Determine the number of ways in which postage of r cents can be pasted on an envelope using 2 1-cent, 3 2-cent and 2 5-cent stamps. • Assume that the order the stamps are pasted on does not matter. • Let ar be the number of ways in which postage of r cents. Then the generating function f(x) of this sequence {ar} is • (1)f(x)=(1+x)(1+x2)(1+x4)(1+x8)(1+x16) • (2)f(x)=(1+x+x2)(1+x2+(x2)2+(x2)3)(1+x5+(x5)2)) • =1+x+2x2+x3+2x4+2x5+3x6+3x7+2x8+2x9+2x10+3x11 +3x12+2x13+ 2x14+x15+2x16+x17+x18。
Example: Use generating functions to determine the number of r-combinations of multiset S={·a1,·a2,…, ·ak }. • Solution: Let br be the number of r-combinations of multiset S. And let generating functions of {br} be f(y), • (1+y+y2+…)k=? f(y)
Example: Use generating functions to determine the number of r-combinations of multiset S={n1·a1,n2·a2,…,nk·ak}. • Solution: Let generating functions of {br} be f(y), • f(y)=(1+y+y2+…+yn1)(1+y+y2+…+yn2)…(1+y+y2+…+ynk) • Example: Let S={·a1,·a2,…,·ak}. Determine the number of r-combinations of S so that each of the k types of objects occurs even times. • Solution: Let generating functions of {br} be f(y), • f(y)=(1+y2+y4+…)k=1/(1-y2)k • =1+ky2+C(k+1,2)y4+…+C(k+n-1,n)y2n+…
Example: Determine the number of 10-combinations of multiset S={3·a,4·b,5·c}. • Solution: Let generating functions of {ar} be f(y), • f(y)=(1+y+y2+y3)(1+y+y2+y3+y4)(1+y+y2+y3+y4+y5) • =1+3y+6y2+10y3+14y4+17y5+18y6+17y7+14y8+10y9+6y10+3y11+y12
Example: What is the number of integral solutions of the equation • x1+x2+x3=5 • which satisfy 0x1,0x2,1x3? • Let x3'=x3-1, • x1+x2+x3'=4, where 0x1,0x2,0x3'
4.6.2 Exponential generating functions • The number of r-combinations of multiset S={·a1,·a2,…,·ak} : C(r+k-1,r), • generating function: The number of r-permutation of set S={a1,a2,…, ak} :p(n,r), generating function:
C(n,r)=p(n,r)/r! Definition 2: The exponential generating function for the sequence a0,a1,…,an,…of real numbers is the infinite series
Theorem 4.17: Let S be the multiset {n1·a1,n2·a2,…,nk·ak} where n1,n2,…,nk are non-negative integers. Let br be the number of r-permutations of S. Then the exponential generating function g(x) for the sequence b1, b2,…, bk,… is given by • g(x)=gn1(x)·g n2(x)·…·gnk(x),where for i=1,2,…,k, • gni(x)=1+x+x2/2!+…+xni/ni! . • (1)The coefficient of xr/r! in gn1(x)·g n2(x)·…·gnk(x) is
Example: Let S={1·a1,1·a2,…,1·ak}. Determine the number r-permutations of S. • Solution: Let pr be the number r-permutations of S, and
Example: Let S={·a1,·a2,…,·ak},Determine the number r-permutations of S. • Solution: Let pr be the number r-permutations of S, • gri(x)=(1+x+x2/2!+…+xr/r!+…),then • g(x)=(1+x+x2/2!+…+xr/r!+…)k=(ex)k=ekx
Example:Let S={2·x1,3·x2},Determine the number 4-permutations of S. • Solution: Let pr be the number r-permutations of S, • g(x)=(1+x+x2/2!)(1+x+x2/2!+x3/3!) • Note: pr is coefficient of xr/r!. • Example:Let S={2·x1,3·x2,4·x3}. Determine the number of 4-permutations of S so that each of the 3 types of objects occurs even times. • Solution: Let p4 be the number 4-permutations, g(x)=(1+x2/2!)(1+x2/2!)(1+x2/2!+x4/4!)
Example: Let S={·a1,·a2, ·a3},Determine the number of r-permutations of S so that a3 occurs even times and a2 occurs at least one time. • Solution: Let pr be the number r-permutations of S so that a3 occurs even times and a2 occurs at least one time, • g(x)=(1+x+x2/2!+…+xr/r!+…)(x+x2/2!+…+xr/r! +…) (1+x2/2!+x4/4!+…)=ex(ex-1)(ex+e-x)/2 • =(e3x-e2x+ex-1)/2
Next: • Recurrence Relations P13, P100
Exercise : • 1.Determine the number of permutations of {1,2,3,4,5,6,7,8} in which no even integer is in its natural position. • 2.Determine the number of permutations of {1,2,…,n} in which exactly k integers are in their natural positions. • 3.Eight boys are seated around a carousel. In how many ways can they change seats so that each has a different boy in front of him? • 4.Let S be the multiset {·e1,·e2,…, ·ek}. Determine the generating function for the sequence a0, a1, …,an, … where an is the number of n-combinations of S with the added restriction: • 1) Each ei occurs an odd number of times. • 2) the element e2 does not occur, and e1 occurs at most once. • 5.Determine the generating function for the number an of nonnegative integral solutions of 2e1+5e2+e3+7e4=n • 6.Determine the number of n digit numbers with all digits at least 4, such that 4 and 6 each occur an even number of times, and 5 and 7 each occur at least once, there being no restriction on the digits 8 and 9.