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Challenge Problem

Challenge Problem. When nitrogen and hydrogen react, they form ammonia gas, which has the formula NH 3 . If 56.0 g of nitrogen are used up in the reaction, how many grams of ammonia will be produced?. N 2 (g) + 3H 2 (g)  2NH 3 (g). ? g NH 3 = 56.0 g N 2. 1 mol N 2. 2 mol NH 3.

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Challenge Problem

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  1. Challenge Problem • When nitrogen and hydrogen react, they form ammonia gas, which has the formula NH3. If 56.0 g of nitrogen are used up in the reaction, how many grams of ammonia will be produced? N2 (g) + 3H2 (g)  2NH3 (g) ? g NH3 = 56.0 g N2 1 mol N2 2 mol NH3 17g NH3 = 68g NH3 28g N2 1 mol N2 1 mol NH3 Episode 802

  2. 4Na (s) + O2 (g)  2Na2O (s) • Sodium metal reacts with oxygen to produce solid sodium oxide. How many grams of sodium must react to produce 42.0 grams of sodium oxide? • When 12.0 grams of hydrogen reacts with oxygen, how many grams of water are produced? ? g Na = 42.0g Na2O 1 mol Na2O 4 mol Na 23g Na 62g Na2O 2 mol Na2O 1 mol Na = 31g Na 2H2 (g) + O2 (g)  2H2O (l) ? g H2O = 12.0g H2 1 mol H2 2 mol H2O 18g H2O 2g H2 2 mol H2 1 mol H2O = 108g H2O Episode 802

  3. Actual Yield • Amount of product produced when the reaction is performed in a lab • Theoretical Yield • Amount of product expected to be produced based on the balanced equation and the amount of reactants • Calculated using stoichiometry • Percent Yield • (actual yield/theoretical yield) x 100% Episode 802

  4. Percent Yield in Lab • Actual yield of CO2 = 0.13g • (from lab data) • Calculated theoretical yield from the balanced equation: NaHCO3 + HCl NaCl + CO2 + H2O ? g CO2 = 0.23g NaCO3 1mol NaCO3 1mol CO2 44g CO2 84g NaCO3 1mol NaCO3 1mol CO2 = 0.12g CO2 0.13g 108% % yield = x 100 = 0.12g Episode 802

  5. What is the % yield of carbon dioxide when 5.99 grams of propane are burned and 12.052 grams of carbon dioxide are collected? C3H8 + 5O2 3CO2 + 4H2O ? g CO2 = 5.99g C3H8 1 mol C3H8 3 mol CO2 44g CO2 44g C3H8 1 mol C3H8 1 mol CO2 = 17.97g CO2 12.052g 67% % yield = x 100 = 17.97g Episode 802

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