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Explore revenue calculation for duct tape wallets at a market stall. Learn to formulate and graph equations for different pricing strategies.

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Check it out!

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  1. Check it out! 2.2.1: Solving Linear Inequalities in Two Variables

  2. Read the scenario. Use the information to complete the problems that follow. • Sanibel wants to sell duct tape wallets at the farmer’s market. She bought $20 worth of tape to get started. She plans to charge $2.50 per yard of duct tape that she uses for each wallet, to pay for both the tape and for the time she spends making each wallet. 2.2.1: Solving Linear Inequalities in Two Variables

  3. Write an equation to show Sanibel’s revenue per wallet. Graph the equation using graph paper. What happens if Sanibel decides to charge $4 per yard? Write a new equation and graph the equation on graph paper. 2.2.1: Solving Linear Inequalities in Two Variables

  4. Write an equation to show Sanibel’s revenue per wallet. Write the equation in slope-intercept form (y = mx + b). Use the information from the scenario to fill in the equation. Let x = the amount of tape used to make each wallet. Sanibel plans to charge $2.50 per yard of tape. Charge for tape used = 2.50x Sanibel spent $20 on supplies. Since she hasn’t sold any wallets yet, show this amount as a negative. Initial cost for tape = –20 y =2.50x –20 2.2.1: Solving Linear Inequalities in Two Variables

  5. Graph the equation. 2.2.1: Solving Linear Inequalities in Two Variables

  6. What happens if Sanibel decides to charge $4 per yard? Write a new equation and graph it. Modify the equation you wrote for problem 1 to reflect the new price per yard. Original equation: y = 2.50x – 20 Substitute the new price, $4, for the old price, $2.50. New equation: y = 4x – 20 2.2.1: Solving Linear Inequalities in Two Variables

  7. Now graph it. 2.2.1: Solving Linear Inequalities in Two Variables

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