1 / 40

Honors Chemistry Final Exam Review

Honors Chemistry Final Exam Review. Good Luck!!!. Convert 15.2 m/s to km/hr. 54.7 km/hr 0.912 km/hr 4.22 km/hr 5.47 x 10 7 not listed. Converting Word Equations into Chemical Equations. Strontium iodide + Lead (II) phosphate  Strontium phosphate + lead (II) iodide.

erma
Download Presentation

Honors Chemistry Final Exam Review

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Honors ChemistryFinal Exam Review

  2. Good Luck!!!

  3. Convert 15.2 m/s to km/hr • 54.7 km/hr • 0.912 km/hr • 4.22 km/hr • 5.47 x 107 • not listed

  4. Converting Word Equations into Chemical Equations Strontium iodide + Lead (II) phosphate  Strontium phosphate + lead (II) iodide SrI2 + Pb3(PO4)2 ----> Sr3(PO4)2 + PbI2 3 3

  5. Practice Quiz Net Ionic Equations • Write the molecular, complete ionic, and net ionic equations for this reaction: Silver nitrate reacts with calcium chloride Molecular: 2AgNO3 + CaCl2  2AgCl + Ca(NO3)2 Complete Ionic: 2Ag+ + 2NO3-+ Ca2+ + 2Cl-  2AgCl + Ca2+ + 2NO3- Net Ionic: 2Ag++ 2Cl-  2AgCl

  6. Mixed Practice • State the type, predict the products, and balance the following reactions: • BaCl2 + H2SO4 • C6H12 + O2  • Zn + CuSO4  • Cs + Br2  • FeCO3  Double Displacement Combustion Single Displacement Synthesis Decomposition

  7. Try This… • Predict the products, balance the following reactions and show the change in oxidation numbers : • Zinc reacts with aqueous copper (II) sulfate • Zinc is higher relative activity so… Zn + CuSO4  Cu + ZnSO4 Each Zn loses 2e- oxidation, reducing agent Each Cu(II)gains 2e- reduction, oxidizing agent

  8. x 6.02x1023 molecules 1 mol H2O x 1 mol H2O 18.02 g H2O Review Mass-Mole-Molecules: Determine the number of molecules in 73 g of water # H2O molecules = 73 g H2O = 2.4 x 1024 molecules H2O

  9. x 253.80 g I2 1 mol I2 x 3 mol I2 2 mol Al Try this one: Calculate the mass in grams of iodine required to react completely with 0.50 moles of aluminum. Al + I2 AlI3 2Al + 3 I2 2 AlI3 0.50 mol Al = 190 g I2

  10. x 253.80 g I2 1 mol I2 x 3 mol I2 x 1 mol Al 2 mol Al 26.98 g Al Try this one: Calculate the mass in grams of iodine required to react completely with 0.50 g of aluminum. Al + I2 AlI3 2Al + 3 I2 2 AlI3 0.50 g Al = 7.1 g I2

  11. What mass of ZnO is formed when 20.0 g of MoO3 is reacted with 10.0 g of Zn? x 1 mol MoO3 x 3 mol Zn x 65.39 g Zn 2 mol MoO3 1 mol Zn 143.94 g MoO3 3 Zn + 2 MoO3 Mo2O3 + 3 ZnO 20.0 g MoO3 = 13.6 g Zn

  12. What mass of ZnO is formed when 20.0 g of MoO3 is reacted with 10.0 g of Zn?We need 13.6 g of Zn so Zn is limiting! x 1 mol Zn x 3 mol ZnO x 81.39 g ZnO 3 mol Zn 1 mol ZnO 65.39 g Zn 3 Zn + 2 MoO3 Mo2O3 + 3 ZnO 10.0 g Zn = 12.4 g ZnO

  13. x 118.00 g SbI3 x 100 130.1 g SbI3 Determine the percent yield if 118.00 g of antimony (III) iodide is produced. 130.1 g of Sbl3 should have been produced. What is the percent yield? 2Sb + 3 I2 2 SbI3 = 90.70 % Yield

  14. Empirical Formulas: 72% iron and 28% oxygen Determine the formula for this substance. moles of Fe 72 g Fe 55.85 g/mole = 1.29 moles Fe moles of O = 28 g O 16.00 g/mole = 1.75 moles O Formula:

  15. Empirical Formulas #9: 72% iron and 28% oxygen Determine the formula for this substance. Multiply subscripts by 3 to get

  16. How much water do I need to add to 250 mL of 3.0 M HCl to dilute it to 1.0 M HCl? 3.0 M HCl x 0.250 L = 1.0 M HCl x L = 0.75 L Total, therefore 0.50 L

  17. Name HCl. • Hydrogen chloride • Hydrochloric acid • Chloric acid • Perchloric acid • Chlorous acid • Hypochlorus acid • I have no idea!! • Who cares??

  18. Name HClO4. • Hydrogen chloride • Hydrochloric acid • Chloric acid • Perchloric acid • Chlorous acid • Hypochlorus acid • I have no idea!! • Who cares??

  19. Name Fe(OH)3 • Iron (III) Hydroxide • Iron Hydroxide • Ironic Acid • Iron (I) Hydroxide • Iron Oxyhydride • Not listed

  20. Which of the following definitions of an acid includes conjugate acids? • Arrhenius • Bronsted-Lowry • Lewis • Kenzig • Woods • Toburen • Sabol • Sanson

  21. Identify the conjugate base in the following equation. • NH3 • H2O • NH4+ • OH-

  22. H2O + CO32- OH- + HCO3According to Bronsted-Lowry theory, in the above reaction, H2O is a(n) • Acid • Base • Conjugate acid • Conjugate base

  23. According to Lewis theory, PCl3 is a(n) • Acid • Base • Salt • Conjugate Acid • Conjugate Base

  24. The pOH of a 0.0030M solution of H2SO4 is: • 2.52 • 11.48 • 2.22 • 11.78 • 0.99 • 13.01

  25. 100.0 mL of 3.000 M nitric acid neutralizes 3.000 M of aluminum hydroxide. How many mL of the base did you use? • 100.0 mL • 50.00 mL • 33.33 mL • 16.67 mL • 8.333 mL • Not listed

  26. Learning Check A gas has a volume of 675 mL at 35°C and 0.850 atm pressure. What is the temperature in °C when the gas has a volume of 0.315 L and a pressure of 802 mm Hg?

  27. Calculation • P1 = 0.850 atm V1 = 675 mL T1 = 308 K • P2 = 1.06 atm V2 = 315 mL T2 = ?? P1 V1 P2 V2 = P1 V1T2= P2 V2 T1 T1T2 T2 = 1.06 atm x 315 mL x 308 K 0.850 atm x 675 mL T2 = 179 K - 273 = -94 °C = 179 K

  28. Zinc will react with hydrochloric acid. The hydrogen gas is collected through water at 30.0oC and 782 mm Hg. The vapor pressure of water at 30.0oC is 32.0 mm Hg. What is the partial pressure of H2? • 250 atm • 314 atm • 0.329 atm • 0.987 atm • Not listed

  29. Zinc ( 65.39 g/mole) will react with hydrochloric acid. Determine the grams of zinc that must be reacted to produce this quantity of hydrogen if the volume is 142 mL . (P = 0.987 atm, T = 30.0oC) • 0.112 g • 1.18 g • 628 g • 0.000 628 g • 0.369 g

  30. When a gas forms a liquid, which process is taking place? freezing condensation boiling evaporation Chemical or Physical

  31. Chemical or Physical Based on the melting points shown in the table, which material would still be a solid at 400°C? beeswax gold lead oxygen Substance Melting Point (°C) Beeswax 62 Gold 1,063 Lead 327 Oxygen –218

  32. A chemical change for a piece of metal would be being bent in half. getting cut into two pieces. being painted. getting rusty.

  33. States of Matter List the Location of Each Change of State Melting Condensation Boiling Energy Gas Energy Liquid Energy Solid Deposition Freezing Sublimation

  34. List the Location of Each Enthapy Used to Change State Heat of Fusion Heat of Vaporization Energy Gas Energy Liquid Energy Solid

  35. Determine the energy released in joules as a 152.00 g sample of metal (0.0335 cal/goC cools 51.5oC • q = cp x m x t: • q = x J • cp= 0.0335 cal/goC (4.184 J/cal) • m = 152.00 g • t = -51.5oC x = (0.140164 J/goC )(152.00 g)(-51.5 oC) = -1.10 x 103 J

  36. Zinc will react with hydrochloric acid. What are the 2 products for this reaction? • ZnCl + H • ZnCl + H2 • Zn2Cl + H2 • ZnCl2 + H2 • Not listed

  37. Zinc will react with hydrochloric acid. What kind of reaction is this? • DD • SD • Synthesis • Decomposition • Not listed

  38. Zinc will react with hydrochloric acid. This reaction will form ZnCl2 + H2. What are the 4 coefficients for the balanced chemical equation? • 1,2,1,2 • 2,1,2,1 • 1,1,1,1 • 2,2,1,2 • Not listed

  39. As you leave Chemistry always remember: You may not be perfect... but parts of you are excellent!!!

  40. The End!!!

More Related