100 likes | 253 Views
Developing Formulas for Triangles and Quadrilaterals. Geometry CP2 (Holt 10-1) K. Santos. Area of a Parallelogram. Area = product of its base and height A= bh Base must be perpendicular to the height b h 5cm 3cm 9cm A = 9(3) A = 27 .
E N D
Developing Formulas for Triangles and Quadrilaterals Geometry CP2 (Holt 10-1) K. Santos
Area of a Parallelogram Area = product of its base and height A= bhBase must be perpendicular to the height b h 5cm 3cm 9cm A = 9(3) A = 27
Area of a Triangle Area = one half of the product of its base and height A= bh or A = Base perpendicular to height h h h b b b If b = 4” and h = 6” Then A = (4)(6) A = (24) A = 12
Area of a Trapezoid Area = (average of the bases)(height) A = h h Remember: height is perpendicular to both bases
Example --Trapezoid Find the area of the trapezoid. 20 in 25 in 18 in 36 in A = h A = 18 A = 18 A = 28(18) A = 504
Area of a Rhombus The area of a rhombus is half the product of the lengths of its diagonals. A = Example: Find the area if the diagonals are: 6 in and 8 in A = A = A = A = 24
Area of a Kite The area of a kite is half the product of the lengths of its diagonals. A = Example 1: Kite with diagonals 9 cm & 8 cm A = A = A = A = 36
Formulas Square: A = bh Rectangle: A = bh Parallelogram: A = bh Trapezoid: A = h Triangle: A = ½ bh Rhombus: A = Kite: A =
Area Addition Postulate The area of a region is equal to the sum of the areas of its nonoverlappingparts. Best way to find this area is to find the area of rectangle + area of triangle
Example—Partitioning Shapes Find the area of the shape below: 4 9 14 13 16 Find the sum of the areas of the rectangle and the triangle A = bh A = A = 4(14) A = A = 56 A = 30 total area: 56 + 30 = 86