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Lecture 12: Electroweak. Kaon Regeneration & Oscillation The Mass of the W The Massless Photon & Broken Symmetry The Higgs Mixing and the Weinberg Angle The Mass of the Z Z Decay. Useful Sections in Martin & Shaw:. Chapter 9, Chapter 10. Regeneration.
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Lecture 12: Electroweak • Kaon Regeneration & Oscillation • The Mass of the W • The Massless Photon & Broken Symmetry • The Higgs • Mixing and the Weinberg Angle • The Mass of the Z • Z Decay Useful Sections in Martin & Shaw: Chapter 9, Chapter 10
Regeneration Ko, Kostates of definite strangeness KL KL + KS strong interaction with matter picks out Ko & Ko which then re-mix So what are kaons??? that depends... who wants to know?! K1o, K2ostates of definite CP KSo, KLostates of definite lifetime
Regeneration Ko, Kostates of definite strangeness ''Regeneration" KL KL + KS strong interaction with matter picks out Ko & Ko which then re-mix So what are kaons??? that depends... who wants to know?! K1o, K2ostates of definite CP KSo, KLostates of definite lifetime
Strangeness Oscillation K2o = 1/2 ( KoKo ) K1o = 1/2 ( Ko + Ko ) Ko = 1/2 ( K1oK2o ) AK(t) = 1/2 ( AS(t) AL(t) ) Strangeness Oscillation: Amplitudes for decaying states KSo and KLo as a function of time are AS(t) = AS(0) exp(imSt) exp(St/2)Sℏ/S AL(t) = AL(0) exp(imLt) exp(Lt/2)Lℏ/L or Ko = 1/2 ( K1o + K2o ) ≃ 1/2 ( KSo + KLo ) ≃ 1/2 ( KSoKLo ) AK(t) = 1/2 ( AS(t) + AL(t) )
Strangeness Oscillation Intensities I(Ko) = 1/2 [AS(t) AL(t)][AS*(t) AL*(t)] = 1/4 {exp(St) + exp(Lt) 2 exp[(S+L)t/2] cosmt } Ko Ko Thus, if we start with a pure Ko beam at t=0, the intensity at time t will be (setting AS(0) = AL(0) = 1) I(Ko) = 1/2 [AS(t) + AL(t)][AS*(t) + AL*(t)] = 1/4 {exp(St) + exp(Lt) + 2 exp[(S+L)t/2] cosmt } and similarly, wherem mLmS = 3.49x1012 MeV (m/m ≃ 7x1015)
K, W and Z A B C D E F G H I J L M N O P Q R S T U V X Y
Weak Coupling & the W Mass M = 42 / GF CERN, 1983 MW = 80 GeV !! M ~ 100 GeV Recall that the ''matrix element" for scattering from a Yukawa potential is fVo = g2/(q2+M2) In the Fermi theory of decay, this is what essentially becomes GF or, more precisely, GF/2 = g2/(q2+M2) = 4W/(q2+M2) GF2 and the relatively small value of GF characterizes the fact that the weak interaction is so weak We can get this small value either by making W small or by making M large UNIFICATION !! So what if we construct things so W = ??? Assuming M ≫ q2 , = 1/137 GF = 105 GeV2
u u d hadrons e, , W- u u d e-, -, - hadrons Stochastic Cooling Electron Cooling p p
Electroweak Interlude A Brief Theoretical Interlude (electroweak theory... at pace!!)
Weak Isospin ( )L ( )L ( )L ( )L ( )L ( )L e e u d c s t b e e W+ But how can this be the ''same" force when the W’s are charged and the photon certainly isn’t !? Is there a way we can ''bind up" the W’s along with a neutral exchange particle to form a ''triplet" state (i.e. like the pions) ?? Well, like with the pions, we seem to have a sort of ''Weak" Isospin since the weak force appears to see the following left-handed doublets as essentially two different spin states: IW(3) = 1/2(like p-n symmetry) Thus, in the process The W+ must carry away +1 units of IW(3) so let’s symbolically denote W+ and, similarly, W If IW = 1 for the W’s then, similar to the o, there is also a neutral state: Wo 1/2 ( ) (which completes the triplet)
The Higgs Higgs Mechanism There is, however, another orthogonal state: 1/2 ( ) If we ascribe this to the photon, then perhaps we might expect to see weak ''neutral currents" associated with the exchange of a Wo with a similar mass to the W so we’d have a nice ''single package" which describes EM and weak forces! Hold on... any simple symmetry is obviously very badly broken the photon is massless and the W’s are certainly not! The photon is also blind to weak isospin and also couples to right-handed leptons & quarks as well Assume the symmetry was initially perfect and all states were massless Then postulate that there exists some overall (non-zero) ''field" which couples to particles and gives them additional virtual loop diagrams : (kind of like an ''aether" which produces a sort of ''drag") but in the limit of zero momentum transfer (rest mass), so represent as
Mixing: the Photon & Z Further suppose that this field is blind to weak isospin and, thus, allows for it’s violation. This would allow the neutral weak isospin states to mix like with the mesons(the W are charged and cannot mix) We will call the ''pure," unmixed statesWoand And we will call the physical, mixed statesZoand
Masses and Couplings GW GW M2W = W + W GW GG GW GW M2W = W + W + GG GW GG GG M2 = + + Wo M2Wo = GW2 Wo + GW GG M2 = GG2 + GW GG W Think about mathematically introducing this Higgs coupling by applying some ''mass-squared" operator to the initial states (since mass always enters as the square in the propagator) where the right-most terms represent the weak isospin - violating terms Assume couplings to W’s are all the same (GW) but coupling to may be different (GG ) MW2 = GW2 For the W the mass would then simply be given by (where G2 contains the coupling plus a few other factors) For the latter 2 equations, we can think of M2 as an operator which yields the mass-squared, M2 , for the coupled state:
Massless Photon / Massive Z GW GG (M2-GG2) = Wo GW2 GG2 (M2-GG2) M2Wo = GW2 Wo + Wo Thus, associate M2 = 0 and MZ2 =GW2 + GG2 From the second of these: Substituting into the first: M4 M2 GG2 = M2 GW2 GW2 GG2 + GW2 GG2 M2 ( M2 GG2 GW2) = 0 M2 = 0orM2 = GW2 + GG2 Note also that MZW
Weinberg Angle & Z Mass W ''Weinberg Angle" tan W = GG / GW ''anomaly condition" ''unification condition" Ql + 3Qq = 0 (leptons) (quarks) MZ = MW/cosW We can parameterize the as a mixture of Wo and as follows: sinWWo cosW M2 = M2 ( sinW Wo cosW) = 0 Thus, applying M2 : 0 = ( GG2+ GW GGW ) sinW (GW2Wo GW GG cosW GW GGsinW GW2 cosW = 0 Coefficient of Wo GG2sinW GW GGcosW = 0 Coefficient of MZ2/MW2 = (GW2 + GG2)/GW2 = 1/cos2W is satisfied separately for each generation
Neutral Current Event Neutral Current Event (Gargamelle Bubble Chamber, CERN, 1973) p
Z Discovery MZ = 91 GeV (predicted) Z e+ e MZ = 91 GeV(observed!!) From comparing neutral and charged current rates sin2W = 0.226 MW = 80 GeV
Flavour-changing neutral currents ( ) ( ) u d cosqC + s sinqC u d´ pre-ABBA weak doublet = = (d cosqC + s sinqC) (d cosqC + s sinqC) u u Z0 Z0 uu + (dd cos2qC + ss sin2qC) + (sd + ds ) sinqC cosqC DS = 0 DS = 1 While we’re here... So, consider the coupling to the Z0 : + Probability ∝ product of wave functions: “Flavour-Changing Neutral Currents” never seen!
GIM mechanism ( ) ( ) ( ) ( ) c s cosqC- d sinqC u d cosqC + s sinqC u d´ c s´ = = (d cosqC + s sinqC) (d cosqC + s sinqC) u u Z0 Z0 + (s cosqC- d sinqC) (s cosqC- d sinqC) c c Z0 Z0 + + uu + cc + (dd+ss)cos2qC + (ss+dd) sin2qC) + (sd + ds - sd - sd) sinqC cosqC DS = 0 DS = 1 Postulate 2 doublets: (Glashow, Iliopolis & Maiaini: “GIM” mechanism) &
Resonant Cross Section formation ''rate" of initial state Blam ! prob for decay to particular final state given the total number of available states ( ) dP dN Transition Rate W = 0 ( ) ( ) dP dE dE dN 0 = dP 1 f dE 2 (E-E0)2 + 2/4 = ( ) ( ) 1 1 V q2 dq d (2)3 dE dN dE = But recall that W = vB / V ( ) 1 V q2 2 v 0f q2 (E-E0)2 + 2/4 = (recall = ℏ/)
Relativistic Treatment But this is non-relativistic! From considering scattering from a Yukawa potential (which followed from the relativistic Klein-Gordon equation) we found the ''propagator" 1/(q2 + M2) So consider the diagram: Under a fully relativistic treatment, q is the 4-momentum transfer and, if we sit in the rest frame of the intermediate state, q2 = p2 E2 = E2 Also note that, for a decaying state, the intermediate mass takes on an imaginary component M M i /2 since ~ exp(iE0t) = exp(iMt) exp{i(Mi/2)}t = exp(iMt) exp(t/2)
Relativistic Breit-Wigner 1 (Mi/2)2 E2 1 M2 /4 iM E2 1 M2 iM E2 = ≃ (in the limit ≪ M) ( )( ) 1 M2 iM E2 1 (E2 M2)2 + M2 1 M2 iM E2 = ~ compare 0f q2 (E-E0)2 + 2/4 and we’d expect something like M20f E2 (E2-M2)2 + M22 = ~ M20f E2 (E2 M2)2 + M22 = CM CM Thus, the propagator goes like And the cross section will be proportional to the square of the propagator : so, roughly, /2 M In fact, a full relativistic treatment yields
The Z Resonance [ ] MZ2 eeX E2 (E2 MZ2)2 + MZ22 (e+e X)= CM CM eeX BreeBrX= Thus, for the production of Z0 near resonance and the subsequent decay to some final state ''X" : since ee can be related by time-reversal to ee Peak of resonance MZ Height of resonance product of branching ratios
Z Decay: Generation Limit ''Invisible modes" Neutrinos !! (limit for light, ''active" neutrinos) Results: hadrons= 1.741 0.006 GeV MZ = 91.188 0.002 GeV Z = 2.495 0.003 GeV ll= 0.0838 0.0003 GeV ≠ 2.495 !! 1.741 + (3 x 0.0838) = 1.9924 So what’s left ???
End To Generation Game An End To The Generation Game ??? (not necessarily a bad thing!)