1 / 13

Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

Engineering 25. Chp4 Tutorial: Prob 4.35 Solution. Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege.edu. Problem 4.35. The Situation Cable Supported Weight. = 6ft. 3ft =. = 2000 lbs = 2 kip. Find Minimum Value for L AC subject to Constraint

fitzgerald-benjamin
Download Presentation

Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Engineering 25 Chp4Tutorial: Prob 4.35Solution Bruce Mayer, PE Licensed Electrical & Mechanical EngineerBMayer@ChabotCollege.edu

  2. Problem 4.35 • The Situation • Cable Supported Weight = 6ft 3ft = = 2000 lbs= 2 kip • Find Minimum Value for LAC subject to Constraint • TAB & TAC Both ≤2000 lbs

  3. Develop Solution on BD

  4. When in Doubt → Plot • Plot TAB & TAC vs LAC • Locate LACmin TAB Limits 4.05 ft

  5. When in Doubt → Plot • Zoom-In on Answer • Locate LACmin more Precisely TAB Limits 4.025 ft

  6. The Command Session >> run Prob4_35_Loaded_Cables Minimum value for LAC in ft = 4.0260 TAB at LACminimum in kip => 1.9993 TAC at LACminimum in kip => 1.7878 Support Angle at LACminimum in ° => 36.8932 index of LACmin => 139

  7. TriAngle Template

More Related