1 / 13

Linear Kinematics - displacement, velocity and acceleration Contents: Quandary New formula

Linear Kinematics - displacement, velocity and acceleration Contents: Quandary New formula Deriving the rest of the formulas How to solve these: suvat Whiteboards. A new formula :. x - displacement (m) v i - initial velocity (m/s) v f - final velocity (m/s)

flinn
Download Presentation

Linear Kinematics - displacement, velocity and acceleration Contents: Quandary New formula

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Linear Kinematics - displacement, velocity and acceleration • Contents: • Quandary • New formula • Deriving the rest of the formulas • How to solve these: suvat • Whiteboards

  2. A new formula: x - displacement (m) vi - initial velocity (m/s) vf - final velocity (m/s) a - acceleration (m/s/s) t - time (s) • x = (vi + vf)t • 2 A car goes from 14 m/s to 26 m/s in 10. seconds. How far does it go in this time? • x = (14 m/s + 26 m/s)(10. s) = 200 m = 2.0 x 102 m • 2 A person starts from rest and goes 14.5 m in 3.75 s. What is their final velocity? • 14.5 m = (0 + vf)(3.75 s), vf = 7.73333 = 7.73 m/s • 2 TOC

  3. Deriving: - 2 more nifty formulas!! • vf = vi + at • x = (vi + vf)t • 2 • From the first formula: • t = (vf - vi) • a • Derive: • vf2 = vi2 + 2ax • x = vit + 1/2at2 • when to use which one… x - displacement (m) vi - initial velocity (m/s) vf - final velocity (m/s) a - acceleration (m/s/s) t - time (s) TOC

  4. Whiteboards: How Far 1 | 2 | 3 | 4 TOC

  5. What distance does a train go if it slows from 32.0 m/s to 5.0 m/s in 135 seconds? • x = ?, vi = 32.0 m/s, vf = 5.0 m/s, t = 135 s • x = (vi + vf)t • 2 • x =2497.5 m, 2500 m W 2500 m

  6. A car going 12 m/s accelerates at 1.2 m/s/s for 5.0 seconds. What is its displacement during this time? x = ?, vi= 12 m/s, vf = ??, a = 1.2 m/s/s, t = 5.0 s x = vit + 1/2at2 x =75 m, 75 m W 75 m

  7. Another car with a velocity of 27 m/s stops in a distance of 36.74 m. What was its acceleration? x = 36.74 m, vi = 27 m/s, vf = 0, a = ??, t = ?? vf2 = vi2 + 2ax a =-9.9211 m/s/s, -9.9 m/s/s W -9.9 m/s/s

  8. A ship slows from 18 m/s to 12 m/s over a distance of 312 m. What time did it take? • x = 312 m, vi = 18 m/s, vf = 12 m/s, t = ?? • x = (vi + vf)t • 2 • t =20.8 s, 21 s W 21 s

  9. A car’s brakes slow it at 9.5 m/s/s. If it stops in 47.3 m, how fast was it going to start with? x = 47.3 m, vi = ??, vf = 0, a = -9.5 m/s/s, t = ?? vf2 = vi2 + 2as vi =29.9783255 m/s, 30. m/s W 30. m/s

  10. A cart stops in a distance of 3.81 m in a time of 4.51 s. What was its initial velocity? • x = 3.81 m, vi = ??, vf = 0, t = 4.51 s • x = (vi + vf)t • 2 • vi =1.68958 m/s, 1.69 m/s W 1.69 m/s

  11. What time will it take a car going 23 m/s to start with, and accelerating at 3.5 m/s/s, to go 450 m? x = 450 m, vi = 23 m/s, vf = ??, a = 3.5 m/s/s, t = ?? x = vit + 1/2at2 (Oh Nooooooo!) OR - use vf2 = vi2 + 2as - find vf, and use vf = vi + at t =10.7585 s, 11 s W 11 s

  12. Start Basic Problem Solving Is it Bigger than Your Mouth? Yes Cut it up a bit No Eat it Done

  13. Start Basic Problem Solving Write down given quantities Are you done yet? No Apply any formula Yes Circle the answer

More Related