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AP Chemistry. Acids and Bases. Aqueous Equilibria: Acids and Bases. Arrhenius Acids and Bases Acids cause [H+] to increase, bases cause [OH-] to increase Bronsted-Lowry Acids and Bases H + /proton Donor (acid) and H +/ proton Acceptor (base) Lewis Acid and Bases Acids accept electron pair
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AP Chemistry Acids and Bases
Aqueous Equilibria: Acids and Bases Arrhenius Acids and Bases Acids cause [H+] to increase, bases cause [OH-] to increase Bronsted-Lowry Acids and Bases H+ /proton Donor (acid) and H+/proton Acceptor (base) Lewis Acid and Bases Acids accept electron pair Bases donate electron pair
Acid and Base Strengths • Based on extent of dissociation. • Strong Acids Dissociate nearly 100% • If HA H+ + A- • A- is a very weak base. (the conjugate base) • Acid and Conjugate Base explanation of strength. Pair of substances differing only by H+ • HF(aq) + H2O(l) <==> H3O+(aq) + F-(aq) • acid 1 base 2 acid 2 base 1 • H3O+(aq) + OH-(aq) <==> H2O(l) + H2O(l) • acid 1 base 2 acid 2 base 1
Acid and Base Strengths • Taken from State University of West Georgia Chemistry Dept.
Acid and Base Strengths • Taken from State University of West Georgia Chemistry Dept.
Hydronium Ions H5O2+
Dissociation of Water • H2O + H2O <---> H3O1+ + OH1- • The equilibrium expression is products over reactants. • K = [H3O1+] [OH1-] / [H2O] [H2O] • The molarity for the water is a constant at any specific temperature. So • K [H2O] [H2O] = [H3O1+] [OH1-] • The quantity on the right hand side of the equation is formally defined as Kw. The numerical vale for Kw is different at different temperatures. • At 25oC Kw = 1.014 x 10-14 • Kw = K[H2O] [H2O] or Kw = [H3O1+] [OH1-]
Dissociation of Water • Equilibrium constants exist then for both acid dissociation and base. (Ka and Kb) • The higher the Ka, the stronger the acid and the higher the Kb, the stronger the base. • Ka and Kb are related by the previous equation. • Kw = KaKb
Dissociation of Water • As Ka gets larger the strength of the acid gets higher, but Kb must fall. Therefore the stronger the acid, the weaker the conjugate base. • It can now be said that the conjugate base (acid) of a weak acid (base) is a weak base (acid) and the conjugate base (acid) of a strong acid (base) is a worthless base (acid). • The strength of an acid/base is usually given as a pKa value. As pKa is inversely related to Ka, the higher the Ka (the stronger the acid), the lower the pKa value. The same is true of bases.
Calculating pH -log [H+] Power of Hydronium (Hydrogen) P[OH-] = - log [OH]
pH in Solutions of Strong Acids and Strong Bases • Strong acids • Certain acids are known as strong acids. These are acids that fully ionize when placed in water: • HA + H2O A- + H3O+ • Goes to completion and thus • Ka = [A-][H3O+]/[HA] = infinity • Some common strong acids are: • HCl, hydrochloric acid • HBr, hyrdobromic acid • HI, hydroiodic acid • H2SO4, sulfuric acid • HNO3, nitric acid • HClO4, perchloric acid
pH in Solutions of Strong Acids and Strong Bases • Strong Bases • Certain bases are known as strong bases. These are bases that fully ionize when placed in water. • Some common strong bases are: • LiOH, lithium hydroxide • NaOH, sodium hydroxide • KOH, potassium hydroxide • Ca(OH)2, calcium hydroxide • Sr(OH)2, strontium hydroxide • Ba(OH)2, barium hydroxide • Alkaline earth oxides. • Lime (CaO)
Equilibrium in Solutions of Weak Acids • HA(aq) + H2O(l) A-(aq) + H3O+(aq) • The equilibrium constant for a weak acid is • Ka = [H3O+][A-]/[HA] • For a weak acid then Ka << 1 • For a strong acid Ka >> 1 • A common way to express the strength of an acid is the pKa, which is similar in form to the pH • pKa = -log10Ka
Calculating Equilibrium Concentrations in Solutions of Weak Acids • Principle Reaction vs Subsidiary Reactions. • If one of the equilibrium reactions is less than 100 x the extent of the other. • Always check • H2O(l) + H2O(l) <---> H3O+(aq) + OH-(aq) • Kw = 1.0 x 10-14
Percent Dissociation in Solution of Weak Acids • Percent dissociation = [HA] dissociated / [HA] initial x 100%
More Discussion • Acid • HA + S HS+ + A- • Acid Solvent Conjugate acid Conjugate base • Base • HB+ + S HS+ + B • Conjugate acid Solvent Acid Base • B + H2O HB+ + OH- • Kb =
More Discussion • Kw = Ka x Kb • Or pKa + pKb = pKw • Carbonic acid (H2CO3) (Data in H2O) • 1. Ka = 4.3 x 10-7 pKa = 6.37 • 2. Ka = 5.61 x 10 -11 pKa = 10.25 • Explain what happens when the Ka of an acid is smaller than the Ka for H2O.
Polyprotic Acids • A polyprotic acid is one that has multiple ionizable protons, such as H2SO4 or H3PO4. • Each proton has its own equilibrium constant Ka. For example, for a diprotic acid H2A, • H2A(aq) H+(aq) + HA-(aq) Ka1 = [H+][HA-]/[H2A] • HA-(aq) H+(aq) + A-2(aq) Ka2 = [H+][A-2]/[HA-] • In general, Ka1 >> Ka2 >> Ka3. • You can compute the K for the total ionization of the acid. If you add the above equations. • H2A (aq) 2H+(aq) + A-(aq) Ktotal = Ka1*Ka2
Polyprotic AcidsTaken from University of Alberta chemistry dept. • Ionization Constants of Aqueous Polyprotic Acids • Common Formula Dissociation Constant pKa • arsenic acid H3AsO4 K1 = 5.65 x 10-3 2.248 - H2AsO4- K2 = 1.75 x 10-7 6.757 - HAsO42- K3 = 2.54 x 10-12 11.596 • boric acid H3BO3 K1 = 5.78 x 10-10 9.238 • carbonic acid H2CO3 K1 = 4.35 x 10-7 6.361 - HCO3- K2 = 4.69 x 10-11 10.329 • chromic acid H2CrO4 K1 = 3.55 -0.550 • - HCrO4- K2 = 3.36 x 10-7 6.473 • citric acid HOC(CH2COOH)3 K1 = 7.42 x 10-4 3.130 - - K2 = 1.75 x 10-5 4.757 - - K3 = 3.99 x 10-6 5.602 • EDTA C2H4N2(CH2COOH)4 K1 = 9.81 x 10-3 2.008 - - K2 = 2.08 x 10-3 2.683 - - K3 = 7.98 x 10-7 6.098 - - K4 = 6.60 x 10-11 10.181
Polyprotic AcidsTaken from University of Alberta chemistry dept. • Common Formula Dissociation Constant pKa • glycinium ion H3NCH2COOH+ K1 = 4.47 x 10-3 2.350 -(glycine) H2NCH2COOH K2 = 1.67 x 10-10 9.778 • hydrogen sulfide H2S K1 = 1.02 x 10-7 6.992 - HS- K2 = 1.22 x 10-13 12.915 • oxalic acid HOOCCOOH K1 = 5.40 x 10-2 1.268 - HOOCCOO- K2 = 5.23 x 10-5 4.282 • phthalic acid C6H4(COOH)2 K1 = 1.13 x 10-3 2.946 - - K2 = 3.90 x 10-6 5.409 • phosphoric acid H3PO4 K1 = 7.11 x 10-3 2.148 - H2PO4- K2 = 6.23 x 10-8 7.206 - HPO42- K3 = 4.55 x 10-13 12.342 • succinic acid C(CH2)2COOH K1 = 6.21 x 10-5 4.207 - HOOC(CH2)2COO- K2 = 2.31 x 10-6 5.636 • sulfuric acid H2SO4 K1 > 1 negative - HSO4- K2 = 1.01 x 10-2 1.994 • sulfurous acid H2SO3 K1 = 1.71 x 10-2 1.766 - HSO3- K2 = 5.98 x 10-8 7.223
Equilibria in Solutions of Weak Bases • Remember Kw = KaKb
Relation Between Ka and Kb • HA(aq) + H2O(l) H3O+(aq) + A-(aq) • Ka • A-(aq)+ H2O(l) HA(aq) + OH-(aq) • Kb • Kw = KaKb = 1.0 x 10-14 • Ka = Kw / Kb • Kb = Kw / Ka • Knet = K1 x K2 x K3……
Acid-Base Properties of Salts Acid Strength Strong Weak Strong Base Strength Weak Resulting Salt Solution
Acid-Base Properties of Salts • Example #1 • NaOH(aq) + HCl(aq) NaCl(aq) + H2O Strong Base Strong Acid Neutral Salt
Acid-Base Properties of Salts • Example #2 • NaOH(aq) + HF(aq) NaF(aq) + H2O Strong Base Weak Acid Basic Salt
Acid-Base Properties of Salts • Example #3 • NH3(aq) + HCl(aq) NH4Cl(aq) Weak Base Strong Acid Acidic Salt
Acid-Base Properties of Salts • Example #4 • NH3(aq) + CH3COOH(aq) NH4OOCCH3(aq) Weak Base Weak Acid ? Salt • Compare Ka to Kb • Ka = 5.6 x 10-10 of NH4+ • Kb = 5.7 x 10-10 of -OOCCH3 • Salt is Neutral or ?
Acid-Base Properties of Salts • Example #5 • 2NH3(aq) + H2CO3(aq) (NH4)2CO3(aq) Weak Base Weak Acid Acidic Salt • Compare Ka to Kb • Ka = 5.6 x 10-10 of NH4+ • Kb = 1.8 x 10-4 of CO32- • Salt is Basic
Factors That Affect Acid Strength • HA H+ + A- • Extent of dissociation depends on H-A bond strength and Electronegativity (or stability of negative charge) on A. • This explanation works for Halogen acids, Organic oxoacids, or Inorganic oxoacids. • Oxidation # of the Halide is not necessary.
Lewis Acids and Bases • Bronsted-Lowry Acid • Proton Donor • Lewis Acid • Electron Pair Acceptor • Bronsted-Lowry Base • Proton Acceptor • Lewis Base • Electron Pair Acceptor
Lewis Acids and Bases • Lewis Acid • Anything with a vacant valence orbital • Charged or Neutral • Other Examples • Fe+3(aq) + 6CN-(aq) -> Fe(CN)6-3(aq) • Cu+2(aq) + 4NH3(aq) -> Cu(NH3)4+2(aq)