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MJ2A

MJ2A. Ch 13.3 – Subtracting Polynomials. Bellwork. Add using either the vertical or horizontal method (r 2 + 9) + (-4r 2 + 6r + 10) (4x 2 – 7x) + (8x + 5) (c + 4) + (c 2 – c + 6). Solutions. -3r 2 + 6r + 19. 4x 2 + x + 5. C 2 + 10. Assignment Review. Text p. 676 # 11 – 22.

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MJ2A

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  1. MJ2A Ch 13.3 – Subtracting Polynomials

  2. Bellwork • Add using either the vertical or horizontal method • (r2 + 9) + (-4r2 + 6r + 10) • (4x2 – 7x) + (8x + 5) • (c + 4) + (c2 – c + 6) Solutions -3r2 + 6r + 19 4x2 + x + 5 C2 + 10

  3. Assignment Review • Text p. 676 # 11 – 22

  4. Before we begin… • Please take out your notebook and get ready to work… • In the last lesson we work with adding polynomials… • In today’s lesson we will work with subtracting polynomials…. • Again…this is easy…the key is being organized!

  5. Objective 13.3 • Students will subtract polynomials

  6. Quick Review • Remember way back when…we discussed subtracting integers and we said that you don’t subtract integers you add the opposite… • We will use this strategy in today’s lesson to subtract polynomials… • What that means is you have to change the signs of each term before you add them…

  7. Subtracting Polynomials • When subtracting polynomials you will use the vertical method… • That is because you have to change the subtraction to addition and change the signs of each term… • It is easier to see what you have done using the vertical method… • Let’s look at an example…

  8. Example #1 • Subtract (5x + 9) – (3x + 6) • Set up the problem vertically 5x + 9 • Change to an addition problem by changing the signs of each term on the bottom row only! + – – 3x + 6 • Then add the like terms 8x + 3

  9. Example #2 • Subtract (4a2 + 7a + 4) – (3a2 + 2) • Set up the problem vertically 4a2 + 7a + 4 + – • Change to an addition problem by changing the signs of each term on the bottom row only! – 3a2 + 2 a2 + 7a + 2 • Then add the like terms

  10. Your Turn • In the notes section of your notebook subtract the following polynomials • (9x + 5) – (4x + 3) • (2x + 4) – (-x + 5) • (3x2 + x) – (8 – 2x) Solutions 5x + 2 3x - 1 3x2 + 3x – 8

  11. Summary • In the notes section of your notebook summarize the key concepts covered in today’s lesson • Today we discussed • Subtracting Polynomials • What strategy will you use? • When changing the signs of the terms which ones will you change?

  12. Assignment • Text p. 680 # 10 – 25 Reminder • This assignment is due tomorrow • I do not accept late assignments • You must show how you got your answer (no work = no credit)

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