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Moles (n) Weight (w) molecule count (N)

Multiply Down to weight and molecule count. Moles (n) Weight (w) molecule count (N). MW. 6.02*10 23. Divide up to moles.

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Moles (n) Weight (w) molecule count (N)

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  1. Multiply Down to weight and molecule count Moles (n) Weight (w) molecule count (N) MW 6.02*1023 Divide up to moles

  2. Micro chip manufacture requires nearly oxygen-free conditions wherein the concentration of O2is at or below 17 pg/L. Given that the atomic mass of O is16g/mol, about how many molecules of O2 /L does this represent ? Note: 1 mol count=6.022*1023 • 5.4*1024 • 3.5*1022 • 5.3*1022 • 3.2*1011 • 6.4*1012 • 1.9*1013 • My answer isn’t above

  3. A sample of 500 atoms of Se are detected by the Mars Rover while traversing the Sinus Miridani plain. What mass of Se was detected by the Rover ? (Se at. Wt.=79 g/mol. Assume 1 mol =6.02*1023 molecules) • 1.52*1020 g • 9.52*10-20 g • 1.051*10-23 g • 6.56*10-20 g • None of the above

  4. You’ve stolen the Mars Rover’s atom detector and discovered 3.01*1020 atoms of a shiny metal in your backyard near the barbecue. The metal sample weighs 13.5 mg. What is the metal ? Note: 1 mol count=6.02*1023 molecules • Au=gold (197 g/mol) • Al (27 g/mol) • Cu (63.5 g/mol) • Fe (55.8 g/mol) • Pb (207 g/mol) • Problem is impossible to solve

  5. Moles: part 2body parts (mole ratio) math: the knee bone is connected to the thigh bone….

  6. How many hands??? 1 6 5 2 3 4 7 9 8 10 11 = 22 hands 2 hands 1 people x 11 people

  7. How many toes connected to the hands (assuming no deformities) ? 5 4 3 2 1 x 10 toes person 5 hands 1 person hand = 50 toes x

  8. Mole parts (ratios) math given 6 moles C3H4O6 How many moles of C ? 6 mol C3H4O6x 3moles C = 1 mol C3H4O6 18 moles C

  9. Mole parts (ratio) math continued Given 45 grams of C6H12O6 …and MW of C6H12O6 =180 g/mol How many grams of C are present ?? First, convert mass to moles (all roads lead through moles) x 1 mole C6H12O6 180 g C6H12O6 45 g C6H12O6 = 0.25 moles C6H12O6

  10. Mole parts (ratio) math continued Next, relate given moles to desired moles via mole ratio (need C moles ) 6 mole C 1 mole C6H12O6 0.25 moles C6H12O6 x ??? =1.5 moles C Finally, convert moles to grams in usual way: 12 g C 1 mole C x 1.5 moles C = 18 g C

  11. Solving Mole parts (ratio) problems • Convert any given weight or molecule count to moles (“all roads lead through moles”) • Relate the computed moles above to desired moles • If necessary, convert desired moles to target grams or molecule count

  12. In-class exercise #3b: chem1114 MoleCalculations: part 2 3.1)mole to mole: how many moles of O are present in 0.1666 mole of C6 H12O6? 1 mol O 3.2) mole to mole how many moles of C6H12O6 can be made with 12 mole of O ? 2moles C6H12O6

  13. In-class exercise #7b: chem 1114 Mole Calculations: part 2 3.3) weight to moles how many moles of C6H12O6 in a sample containing 216 g C ? 3mol 3.4)moles to weight how many grams of C6H12O6 are formed with 0.2666 mol H? = 4 g

  14. 3.5) moles to molecules how many molecules of O are present in 0.8333 mol of C6 H12O6? =5*1023 3.6) molecules to moles how many moles of C6 H12O6 are formed from 5.04*1025 atoms of H ? 7 moles

  15. 3.7 mass to molecules: how many moleculesof C6 H12O6form from 96 g of C ? 8 *1023 molecules ofC6H12O6 3.8 atoms to mass: how many grams of H are combined with 2.7*1024 atoms of O in C6H12O 6 ? 9 grams H

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