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Function: Evaluating

Function: Evaluating. Example 1: Given f ( x ) = 5 – x 2 , find f (- 3). The notation f (- 3) means to replace the independent variable, x with - 3 and calculate the value of the dependent (or function) variable, y .

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Function: Evaluating

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  1. Function: Evaluating Example 1: Given f (x) = 5 – x2, find f (- 3). The notation f (- 3) means to replace the independent variable, x with - 3 and calculate the value of the dependent (or function) variable, y. So here, f (- 3) = 5 – (- 3)2 = - 4 = the y-value or the function value. Example 2: Given f (x) = (x – 4)2, find f (a). Here, replace x with a: f (a) = (a – 4)2 = a2 – 8a + 16. In this case a numerical y- or functional-value has not been found. However, a formula for it in terms of a has been found.

  2. Function: Evaluating Example 3: Given f (x) = x2 + 2x, find f (a + h) – f (a). Here f (a + h) means to replace x with a + h so f (a + h) = (a + h)2 + 2(a + h),f (a + h) =a2 + 2ah + h2 + 2a + 2h, and f (a) means to replace x with a so f (a) = a2 + 2a. To findf (a + h) – f (a), subtract the expressions in yellow above to get: a2 + 2ah + h2 + 2a + 2h – (a2 + 2a), so f (a + h) – f (a) = 2ah + h2 + 2h. Here, the difference between the y-value when x = a + h and the y-value when x = a has been found. Slide 2

  3. Example 4: Given find f (2). Function: Evaluating This function is defined in two pieces. One piece is f (x) = x2. It is defined only for x-values that are  3. The other piece is f (x) = x + 6. It is defined only for x-values that are > 3. Since the function is being evaluated for x = 2 and 2  3, the top piece f (x) = x2 is used. Therefore, f (2) = (2)2 = 4. Slide 3

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