1 / 10

Freefall

Freefall. 1. Acceleration Due to Gravity. Galileo did many experiments and proved that if you ignore air resistance : All objects fall to the earth with uniform acceleration. Mass of the object does not matter. Distance above the ground does not matter.

galena
Download Presentation

Freefall

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Freefall

  2. 1. Acceleration Due to Gravity • Galileo did many experiments and proved that if you ignore air resistance: • All objects fall to the earth with uniform acceleration. • Mass of the object does not matter. • Distance above the ground does not matter. • Objects accelerate at 9.81 m/s2 or 32.2 ft/s2. • This varies slightly because of the distance between the object and the center of the earth.

  3. Uniform Acceleration

  4. Objects dropped will speed up. • Objects thrown up will slow down. • Gravity causes objects to accelerate downward. • Gravity is the attractive force between two objects. • When objects are falling, the only force on them is gravity, and they are in freefall. • Objects in freefall feel “weightless” because the only force is gravity.

  5. 2. Frame of Reference going up : +d, +v a = -g = -9.81 m/s2 Slowing Down • Ground level is the reference. ground level going down : -d, -v a = -g = -9.81 m/s2 Speeding Up

  6. Acceleration due to gravity : -g = -9.81 m/s2 • Use a = -g = -9.81 m/s2 any time an object is moving up or down! • Assume NO air resistance! • efff.gif

  7. Maximum Height Velocity = 0 time = ½ total time +va d = 0 At same height object thrown same velocity, opposite direction d = 0, -va Ground Level

  8. Use the same formulas except use a = 9.81 m/s2 • = ½(vf + vi) • d = ½(vf + vi)t • vf = vi + (-g)t • d = vit + ½(-g)t2 • vf2 = vi2 + 2(-g)d

More Related