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Ch. 9 Momentum and Its Conservation . Milbank High School. Sec. 9.1 Impulse and Momentum . Objectives Compare the system before and after an event in momentum problems Define the momentum of an object Determine the impulse given to an object
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Ch. 9 Momentum and Its Conservation Milbank High School
Sec. 9.1Impulse and Momentum • Objectives • Compare the system before and after an event in momentum problems • Define the momentum of an object • Determine the impulse given to an object • Recognize that impulse equals the change in momentum of an object
Momentum • What is momentum? • The Minnesota Vikings have momentum entering the final weeks of the season… • Anything that is moving has momentum • Depends on what?
Momentum • Momentum = mass * velocity • In physics, the symbol for momentum is “p” sssooo… • p = m * v • kg·m/s Which has more momentum, a supertanker tied to a dock or a raindrop falling?
Momentum • Determine the momentum of a ... • 60-kg halfback moving eastward at 9 m/s. • 60 x 9 = 540 kg·m/s east • 1000-kg car moving northward at 20 m/s. • 1000 x 20 = 20,000 kg·m/s • 40-kg freshman moving southward at 2 m/s. • 40 x 2 = 80 kg·m/s
Impulse and Momentum • Impulse = Change in momentum • Impulse • The product of the average net force exerted on an object and the time interval over which the force acts • N•s
Real Life Applications.. • Sports… • Follow-through! • Gymnastics Mats • Cars… • Airbags! • Before airbags…. • Bumpers • Eggs… • Jumping… • Knees • Shoes
Review • Can a bullet have the same momentum as a truck?
Sec. 9.2The Conservation of Momentum • Objectives • Recognize the conditions under which the momentum of a system is conserved • Apply conservation of momentum to explain the propulsion of rockets • Solve conservation of momentum problems in two dimensions by using vector analysis
The Law of Conservation on Momentum • The total momentum of two objects before a collision is equal to the total momentum of the two objects after the collision.
Two Particle Collisions • Inelastic collisions mAvA1 + mB1vB1 = mAvA2 + mBvB2
Propulsions • We can also use: pA2 = -pB2 mAvA2 = -mBvB2 Example Problem Pg. 212