1 / 73

Chapter 3 Hubs, Bridges and Switches

Chapter 3 Hubs, Bridges and Switches. Interconnecting LANs. Q: Why not just one big LAN? Limited amount of supportable traffic: on single LAN, all stations must share bandwidth Ethernet: limited length: 802.3 specifies maximum cable length

garth-guy
Download Presentation

Chapter 3 Hubs, Bridges and Switches

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Lecture 3 Chapter 3Hubs, Bridges and Switches

  2. Lecture 3 Interconnecting LANs Q: Why not just one big LAN? • Limited amount of supportable traffic: on single LAN, all stations must share bandwidth • Ethernet: limited length: 802.3 specifies maximum cable length • Ethernet: large “collision domain” (can collide with many stations) • collision domain: set of stations such that simultaneous transmission of any two of them will generate a collision • Token Ring: token passing delay per station: 802.5 limits number of stations per LAN:

  3. Lecture 3 Hubs • Physical Layer devices: essentially multi-leg repeaters operating at bit levels: repeat bits received on one interface to all other interfaces • Hubs can be arranged in a hierarchy (or multi-tier design), with backbone hub at its top

  4. Lecture 3 Hubs (more) • Each connected LAN referred to as LAN segment • Hubs do not isolate collision domains: node may collide with any node residing at any segment in LAN • Hub Advantages: • simple, inexpensive device • Multi-tier provides graceful degradation: portions of the LAN continue to operate if one hub malfunctions • extends maximum distance between node pairs (100m per Hub)

  5. Lecture 3 Hub limitations • single collision domain results in no increase in max throughput • multi-tier throughput capacity same as single segment throughput • individual LAN restrictions pose limits on number of nodes in same collision domain and on total allowed geographical coverage • cannot connect different Ethernet types (e.g., 10BaseT and 100baseT) Qn: Why?

  6. Lecture 3 Bridges • Link Layer devices: forward Ethernet frames selectively: • learn where each station is located • examine the header of each frame • forward on the proper link (if known) • if dest. and source on same link, drop frame WHY? • if not known where dest. is, broadcast frame • except on originating link, of course • also called Layer 2 switches

  7. Lecture 3 Bridges • Bridge isolates collisiondomains • buffers frame • then forwards it, if needed, using CSMA/CD • A broadcast frame is forwarded on all interfaces (except the incoming one) • thus broadcast frames propagate across bridges • A set of segments connected by bridges and hubs is called a broadcast domain

  8. Lecture 3 Bridges (more) • Bridge advantages: • Isolates collision domains resulting in higher total throughput capacity, and does not limit the number of nodes nor geographical coverage • Can connect different type Ethernet since it is a store and forward device (e.g. 10 & 100BaseT) • Transparent: no need for any change to hosts LAN adapters (invisible to them)

  9. Lecture 3 Backbone Bridge

  10. Lecture 3 Interconnection Without Backbone • Not recommended for two reasons: - single point of failure at Computer Science hub - all traffic between EE and SE must path over CS segment

  11. Lecture 3 Bridges: frame filtering, forwarding • bridges filter packets • same-LAN -segment frames not forwarded onto other LAN segments • forwarding: • how to know on which LAN segment to forward frame?

  12. Lecture 3 Bridge Filtering • bridges learn which hosts can be reached through which interfaces: maintain filtering tables • when frame received, bridge “learns” location of sender: incoming LAN segment • records sender location in filtering table • filtering table entry: • (Node MAC Address, Bridge Interface, Time Stamp) • stale entries in Filtering Table dropped (TTL can be 60 minutes)

  13. Lecture 3 Bridge Operation pseudocode Init: set filtering table to void Case: frame arrives on port P, src MAC , dest MAC  /* Table Update stage */ if not listed, or mapped to port not equal P then add mapping   P with expiration time else update expiration time /* if listing fits */ /* Frame Forwarding stage */ look up  in filtering table: listing “  Q” /* if listed */ if not listed, forward on all ports except P /* “flood */ else,ifQ= P , drop the frame /* WHY ? */ otherwise,forward the frame on port Q only

  14. Lecture 3 Bridge Learning: example Suppose C sends frame to D and D replies back with frame to C • C sends frame, bridge has no info about D, so floods to both LANs 2 and 3 • bridge notes that C is on port 1 • frame ignored on upper LAN • frame received by D

  15. Lecture 3 Bridge Learning: example C 1 • D generates reply to C, sends it • bridge sees frame from D • bridge notes that D is on interface 2 • bridge knows C on interface 1, so selectively forwards frame out via interface 1 only

  16. Lecture 3 B 2 2 A , 1 A , 1 2 2 1 1 A What will happen with loops?Incorrect learning Frame sent from A to B Problems: (1) frame loops infinitely (2) unstable filtering tables

  17. Lecture 3 Loop-free: tree C B A message from Awill mark A’s location A

  18. Lecture 3 Loop-free: tree C B A:  A message from Awill mark A’s location A

  19. Lecture 3 Loop-free: tree A:  C B A:  A message from Awill mark A’s location A

  20. Lecture 3 Loop-free: tree A:  A:  A:  C B A:  A:  A message from Awill mark A’s location A

  21. Lecture 3 Loop-free: tree A:  A:  A:  C B A:  A:  A message from Awill mark A’s location A

  22. Lecture 3 Loop-free: tree A:  A:  A:  C B A:  A:  A message from Awill mark A’s location So a message toA will go by marks… A

  23. Lecture 3 Disabled Bridges-Spanning Tree • for increased reliability, it is desirable to have redundant, alternative paths from source to dest • this causes cycles - bridges may multiply and forward frame forever • solution: organize bridges in a spanning tree and disable all ports not belonging to the tree

  24. Lecture 3 Introducing Spanning Tree • Objective: Find tree spanning all LAN segments • each bridge transmits on a single port • each LAN transmits on a single bridge • Bridges run the Spanning Tree Protocol • Use a distributed algorithm • Objective: select what ports should actively forward frames, and which ports should accept frames • Bridges communicate using special configuration messages (BPDUs) to perform this selection • BPDU = Bridge Protocol Data Unit • STP standardized in IEEE 802.1D

  25. Lecture 3 Method • Each bridge sends periodically a BPDU to all its neighbors • BPDU contains: • ID of bridge the sender views as root (my_root_ID) • known distance to that root • senders own bridge ID • port ID of the port from which BPDU sent

  26. Lecture 3 Introductory STP In order to help understanding STP we first present it as 3 separate algorithms • How to agree on a root bridge? • How to compute a ST for bridges? • How to compute a ST for LAN segments? Actual STP does all 3 functions in the same iterative process Note: we assume throughout that the network is connected

  27. Lecture 3 1. Choosing a root bridge • Assume • each bridge has a unique identifier (ID) • within a bridge each port has a unique ID • Each bridge remembers smallest bridge ID seen so far (= my_root_ID) • including own ID • Periodically, send my_root_ID to all neighbors (“flooding”) (included in BPDU) • When receiving ID, update if necessary • Qn: Is that enough for universal agreement?

  28. Lecture 3 2. Compute ST given a root Idea: each bridge finds its shortest path to the root  generate shortest paths tree Output: At each node, parent pointer and distance to root (parent=bridge leading to root along shortest path) Spanning tree T: A link belongs to T iff it connects some bridge to its parent Qn: Does this idea fully specify an algorithm producing a spanning tree? How: Bellman-Ford algorithm

  29. Lecture 3 Distributed Bellman-Ford Assumption: There is a unique root node s • this was done in Step 1 Idea: Each node, periodically, tells all its neighbors what is its distance from s But how can they tell? • s: easy. dists = 0always! • Another node v: • Bridge calls the neighbor with least distance to root - its “parent” • If bridges tie: choose bridge with lowest ID

  30. Lecture 3 Why does this work? • Suppose all nodes start with distance , and suppose that updates are sent every time unit. 2 1 ID=21 ID=3 E  1 1 1 D 2 C 1 ID=17 A 1 0 0 0 ID=7 G 3 2 0 1 B 0 2 F Means: BPDU Means: link admitted to bridge spanning tree B sees same distance from A and E; A chosen since has smaller ID

  31. Lecture 3 Bellman-Ford: properties • Works for any positive link weights w(u,v): • Works also when the system operates asynchronously. • Works regardless of the initial distances

  32. Lecture 3 Actual STP What is missing so far?: • Can’t discard redundant links, since we need to connect host, not just bridges • Instead can disable redundant bridge ports leading to them • Graph model too simple, since there can be many bridges on one LAN (see next slide) • We need to look at forwarding paths and not just graph paths STP protocol does all the “steps” together: • Selection of root bridge • Evaluation of distance to root and parent bridge • Selection of the active ports and blocked ports

  33. Lecture 3 Exampleof a network L6 L2 L5 B A D C E L1 L3 F L7 L4 Note: LAN L2 connects three bridges, 4 ports

  34. Lecture 3 STP plan Objective: prune given network to render a forwarding tree, i.e: • between any two hosts there is a single forwarding path through the network, no loops possible Method: Classify all ports into three types: • Root ports: one for each bridge • Designated ports: one for each LAN • All other ports are blocked Root and designated ports transfer data frames in both directions. Blocked ports don’t transfer data

  35. Lecture 3 BPDU’s (1) • Each bridge sends BPDUs on all its ports. • Based on received BPDUs, bridge determines: • determines Root • finds own distance/cost to root • classifies of own ports: root/designated/blocked • The BPDU contains bridge’s current view of: • the root bridge of the network • own distance to this root • own ID number • the sending port’s ID number

  36. Lecture 3 BPDUs (2) • A BPDU is computed by a bridge for each of its ports and sent out on that port • it will reach all ports attached to port’s LAN • STP prerequisites • each bridge is given a bridge ID number • The ID number is unique in the network • Each port is given a port ID number • The port ID is unique within its bridge • ID numbers assigned manually or automatically • Each link (LAN) has a positive cost

  37. Lecture 3 BPDU Processing in a bridge (1) • Determine current view of root: this is lowest root ID received, including own bridge ID. • Only BPDUs reporting this root are considered in sequel • Compare all reported distances to root. own distance to root= lowest received distance + + cost of the link to the reporting bridge

  38. Lecture 3 Designated Ports • all BPDUs received on a port are compared, including own message sent on it; • the best message has: • smallest root ID and • smallest distance to that root • if tied, choose the one with lowest bridge ID • if tied, choose lowest port ID • Qn: When does the last tie happen? • If the message sent by the bridge on that port is best, label it a designated port • there is exactly one designated port on each LAN

  39. Lecture 3 Root Ports • now compare the best messages received on all the ports of the bridge, according to the same criteria as above • the port on which best message was received is labeled root port • root bridge has no root port • there is exactly one root port per bridge • only root and designated ports receive and send data. • BPDU’s are sent periodically • even after convergence of algorithm • indicate bridge is active / discover failures

  40. Lecture 3 Summary • after convergence: • all bridges agree which bridge is the root • each LAN has exactly one designated port • frames from LAN enter the bridge on that port on the way to root (upstream) • frames coming from root exit the bridge on that port on the way to remote LANs (downstream) • all bridges on LAN agree who is the designated port • a LAN may have any ≥ 0 number of root ports on it • each bridge has exactly one root port • the port leads through a LAN to the parent bridge • this is the next bridge on a shortest path to root • a bridge may have any ≥ 0 number of designated ports • a bridge with no designated ports blocks also the root port, and so becomes inactive

  41. Lecture 3 Notes • only bridges make decisions, LANs are passive • More discussion of the validity of STP will be given in homework and recitation

  42. Lecture 3 Example Spanning Tree • Protocol operation: • Pick a root • Each bridge picks a root port B8 B3 B5 B7 B2 B1 B6 B4

  43. Lecture 3 Example Spanning Tree B8 root port Spanning Tree: B3 B5 B1 root port B7 B2 B7 B2 B4 B5 B6 B1 Root B8 B3 B6 LANs not connecting bridgesomitted here B4

  44. Lecture 3 Spanning Tree Protocol: Execution (B8,root=B8, dist=0) B8 B3 ignore msg B5 B7 B2 B1 (B1,root=B1,dist=0) (B1,root=B1, dist=0) B6 B4 WHY? (B4, root=B1, dist=1) (B6, Root=B1, dist=1)

  45. Lecture 3 Bridges vs. Routers • both are store-and-forward devices • routers: network layer devices (examine network layer headers) • bridges are link layer devices • routers have routing tables, use routing algorithms, designed for Wide Area addressing • bridges have filtering tables, use filtering, learning & spanning tree algorithms, designed for local area

  46. Lecture 3 Routers vs. Bridges Bridges + and - + bridge operation is simpler, requiring less processing - topologies are restricted with bridges: a spanning tree must be built to avoid cycles (with routers cycles are avoided by the Layer 3 routing algorithm) - bridges do not offer protection from broadcast storms (endless broadcasting by a faulty host will be forwarded by a bridge)

  47. Lecture 3 Routers vs. Bridges Routers + and - + arbitrary topologies can be supported, cycling is limited by TTL counters (and good routing protocols) + provide barrier protection against broadcast storms - require IP address configuration (not plug and play) - require higher processing • bridges do well in small (few hundred hosts) while routers used in large networks (thousands of hosts) and in Internet core

  48. Lecture 3 Ethernet Switches • = a powerful bridge • layer 2 (frame) forwarding, filtering using LAN addresses • Switching: A-to-B and A’-to-B’ with no collisions • large number of interfaces • often: individual hosts, star-connected into switch • Ethernet w. no collisions! • = Switched Ethernet • often: includes L3 function

  49. Lecture 3 Ethernet Switches • cut-through switching: frame forwarded from input to output port without awaiting for assembly of entire frame • slight reduction in latency • allow combinations of shared/dedicated, 10/100/1000 Mbps interfaces

  50. Lecture 3 Ethernet Switches (more) Dedicated Shared

More Related