1 / 5

Izmjenična struja

Izmjenična struja. B. a. v. b. v. c. d. B. b. v. c. a. v. d. B. b. I. v. a. c. v. d. I. B. c. v. 2r. I. v. a. l. I.  i = B2l  r sin  t. B. , 2rl = S. v.  i = B S  sin  t. .  i  u. r. . U o = BS . Maksimalna vrijednost

gautam
Download Presentation

Izmjenična struja

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Izmjenična struja

  2. B a v b v c d B b v c a v d B b I v a c v d I B c v 2r I v a l I

  3. i= B2l r sin t B , 2rl = S v i= BSsin t  i  u r  Uo = BS Maksimalna vrijednost izmjeničnog napona u = Uo sin t Jednadžba izmj. nap. i = Blv sin i = Iosin t Jednadžba izmj. str. v =  r  =  t ,  = 2f l  2l

  4. u,i t u Uo Io T i

  5. u t Zadatak: Frekvencija gradske mreže je 50 Hz. Koliko puta u svakoj sekundi napon ima vrijednost 0? Za koje vrijeme napon gradske mreže naraste od nule do maksimalne vrijednosti? Rješenje: f = 50 Hz Uo N = 2 f = 250 Hz T t N =100 puta u sekundi , t =0,005 s =5 ms

More Related