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Entry Task: Feb 5 th -6 th Block #1

Entry Task: Feb 5 th -6 th Block #1. Write the Question How many formula units are in 50.0 grams of Iron II oxide? You have 5 minutes!. Agenda:. Discuss Particles <-> Moles<-> Grams Self Check on Concepts Discuss Self-Check Notes on Percent Composition HW: Percent Composition ws.

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Entry Task: Feb 5 th -6 th Block #1

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  1. Entry Task: Feb 5th-6thBlock #1 Write the Question How many formula units are in 50.0 grams of Iron II oxide? You have 5 minutes!

  2. Agenda: Discuss Particles <-> Moles<-> Grams Self Check on Concepts Discuss Self-Check Notes on Percent Composition HW: Percent Composition ws

  3. I can… • Calculate particles moles  grams • Explain what is meant by the percent composition of a compound.

  4. Discuss Particles  Moles  Grams Avervision for answers

  5. Clear off your Desk!! Calculators Periodic Tables Needed

  6. Discuss Self Check Avervision for answers

  7. Percent Composition is the percent of each element in a compound. Percent composition is a step in determining the ratio in elements in a compound/molecule.

  8. Example: Magnesium oxide- MgO By just looking at this compound, It LOOKS like it 50/50 of magnesium oxide. But according to its molar mass, it is not 50/50. Its molar mass is 24.305 g for Mg + 15.999 g for O, = 40.304 g 24.305g (Magnesium mass) 40.304 grams (mass of MgO) Magnesium = 0.60 X 100 = 60% Oxygen 15.999 g (oxygen mass) 40.304 grams (mass of MgO) = 0.40 X 100 = 40%

  9. Iron III oxide Fe2O3 Fe = 55.845 x 2 = 111.69 g  159.687 g 0.6994 X 100 = 69.9%  159.687 g O = 15.999x 3 = 47.997g 0.3005 X 100 = 30.1% 159.687 g

  10. Barium hydroxide Ba(OH)2 Ba= 137.33 g X 1 = 137.33 g  171.3438 g = 0.801 X 100 = 80.1% O= 15.999 g X 2 = 31.998 g  171.3438 g = 0.187 X 100 = 18.7% H= 1.0079 g X 2 = 2.0158 g  171.3438 g = 0.0117 X 100 = 1.2% 171.3438 g

  11. Lead (II) nitrate Pb(NO3)2 Pb= 207.2 g X 1 = 207.2 g  331.208 g = 0.626 x100 = 62.6% N= 14.007 g X 2 = 28.014 g  331.208 g = 0.0845 x100 = 8.46%  331.208 g = 0.289 x100 = 28.9% O= 15.999 g X 6 = 95.994 g 331.208 g

  12. Ammonium sulfate (NH4)2SO4  131.044 X 100 = 21.4 % N= 14.007 g X 2 = 28.014 g H= 1.0079 g X 8 = 8.06 g  131.044 X 100 = 6.2% S= 30.974 g X 1 = 30.974 g  131.044 X 100 = 23.6 % O= 15.999 g X 4 = 63.996 g  131.044 X 100 = 48.8.4 % add up % = 100% 1 mole = 131.044 grams

  13. Hydronium nitride (H3O)3N  71.1 grams x 100= H= 1.0079 g X 9 = 9.071 g = 12.7 % O= 15.999 g X 3 = 47.997 g  71.1 grams x 100= = 67.6 % N= 14.007 g X 1 = 14.007 g  71.1 grams x 100= = 19.7 % 71.1 grams

  14. Aluminum cyanide Al(CN)3 Al= 26.98 g X 1 = 26.98 g  105 grams x 100= = 25.6 %  105 grams x 100= = 34.3 % C= 12.0107 g X 3 = 36.032 g  105 grams x 100= = 40.0 % N= 14.007 g X 3 = 42.021 g 105 grams

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