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More Applications of the Pumping Lemma. The Pumping Lemma:. Given a infinite regular language. there exists an integer (critical length). for any string with length. we can write. with and. such that:. Non-regular languages.
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More Applications ofthe Pumping Lemma Prof. Busch - LSU
The Pumping Lemma: • Given a infinite regular language • there exists an integer (critical length) • for any string with length • we can write • with and • such that: Prof. Busch - LSU
Non-regular languages Regular languages Prof. Busch - LSU
Theorem: The language is not regular Proof: Use the Pumping Lemma Prof. Busch - LSU
Assume for contradiction that is a regular language Since is infinite we can apply the Pumping Lemma Prof. Busch - LSU
Let be the critical length for Pick a string such that: and length We pick Prof. Busch - LSU
From the Pumping Lemma: we can write: with lengths: Thus: Prof. Busch - LSU
From the Pumping Lemma: Thus: Prof. Busch - LSU
From the Pumping Lemma: Thus: Prof. Busch - LSU
BUT: CONTRADICTION!!! Prof. Busch - LSU
Therefore: Our assumption that is a regular language is not true Conclusion: is not a regular language END OF PROOF Prof. Busch - LSU
Non-regular languages Regular languages Prof. Busch - LSU
Theorem: The language is not regular Proof: Use the Pumping Lemma Prof. Busch - LSU
Assume for contradiction that is a regular language Since is infinite we can apply the Pumping Lemma Prof. Busch - LSU
Let be the critical length of Pick a string such that: and length We pick Prof. Busch - LSU
From the Pumping Lemma: We can write With lengths Thus: Prof. Busch - LSU
From the Pumping Lemma: Thus: Prof. Busch - LSU
From the Pumping Lemma: Thus: Prof. Busch - LSU
BUT: CONTRADICTION!!! Prof. Busch - LSU
Therefore: Our assumption that is a regular language is not true Conclusion: is not a regular language END OF PROOF Prof. Busch - LSU
Non-regular languages Regular languages Prof. Busch - LSU
Theorem: The language is not regular Proof: Use the Pumping Lemma Prof. Busch - LSU
Assume for contradiction that is a regular language Since is infinite we can apply the Pumping Lemma Prof. Busch - LSU
Let be the critical length of Pick a string such that: length We pick Prof. Busch - LSU
From the Pumping Lemma: We can write With lengths Thus: Prof. Busch - LSU
From the Pumping Lemma: Thus: Prof. Busch - LSU
From the Pumping Lemma: Thus: Prof. Busch - LSU
Since: There must exist such that: Prof. Busch - LSU
However: for for any Prof. Busch - LSU
BUT: CONTRADICTION!!! Prof. Busch - LSU
Therefore: Our assumption that is a regular language is not true Conclusion: is not a regular language END OF PROOF Prof. Busch - LSU