1 / 21

Solution

Solution. Percent Concentration. Percent Concentration. Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution. Mass-Mass % Concentration. mass/mass % = g solute x 100% 100 g solution.

glora
Download Presentation

Solution

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Solution Percent Concentration ICS

  2. Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution ICS

  3. Mass-Mass % Concentration mass/mass % = g solute x 100% 100 g solution ICS

  4. Mixing Solute and Solvent Solute + Solvent 4.0 g KCl 46.0 g H2O 50.0 g KCl solution ICS

  5. Calculating Mass-Mass % g of KCl = 4.0 g g of solvent = 46.0 g g of solution = 50.0 g %(m/m) = 4.0 g KCl (solute) x 100 = 8.0% KCl 50.0 g KCl solution ICS

  6. Learning Check PC1 A solution contains 15 g Na2CO3 and 235 g of H2O? What is the mass % of the solution? 1) 15% (m/m) Na2CO3 2) 6.4% (m/m) Na2CO3 3) 6.0% (m/m) Na2CO3 ICS

  7. Solution PC1 mass solute = 15 g Na2CO3 mass solution = 15 g + 235 g = 250 g %(m/m) = 15 g Na2CO3 x 100 250 g solution = 6.0% Na2CO3 solution ICS

  8. Mass-Volume % mass/volume % = g solute x 100% 100 mL solution ICS

  9. Learning Check PC2 An IV solution is prepared by dissolving 25 g glucose (C6H12O6) in water to make 500. mL solution. What is the percent (m/v) of the glucose in the IV solution?1) 5.0% 2) 20.% 3) 50.% ICS

  10. Solution PC2 1) 5.0% %(m/v) = 25 g glucose x 100 500. mL solution = 5.0 %(m/v) glucose solution ICS

  11. Writing Factors from % • A physiological saline solution is a 0.85% (m/v) NaCl solution. • Two conversion factors can be written for the % value. 0.85 g NaCl and 100 mL NaCl soln 100 mL NaCl soln 0.85 g NaCl ICS

  12. % (m/m) Factors Write the conversion factors for a 10 %(m/m) NaOH solution NaOH and NaOH soln NaOH soln NaOH ICS

  13. % (m/m) Factors Write the conversion factors for a 10 %(m/m) NaOH solution NaOH and NaOH soln NaOH soln NaOH 10 g 100 g 100 g 10 g ICS

  14. Learning Check PC 3 Write two conversion factors for each of the following solutions: A. 8 %(m/v) NaOH B. 12 %(v/v) ethyl alcohol ICS

  15. Solution PC 3 Write conversion factors for the following: A. 8 %(m/v) NaOH 8 g NaOH and 100 mL 100 mL 8 g NaOH B. 12 %(v/v) ethyl alcohol 12 mL alcohol and 100 mL 100 mL 12 mL alcohol ICS

  16. Using % Factors How many grams of NaCl are needed to prepare 250 g of a 10.0% (m/m) NaCl solution? Complete data: ____________ g solution ____________% or (______/_100 g_) solution ____________ g solute ICS

  17. Calculation using % factors 250 g solution 10.0% or (10.0 g/100 g) solution ? g solute 250 g NaCl soln x 10.0 g NaCl = 25 g NaCl 100 g NaCl soln ICS

  18. Learning Check PC4 How many grams of NaOH do you need to measure out to prepare 2.0 L of a 12%(m/v) NaOH solution? 1) 24 g NaOH 2) 240 g NaOH 3) 2400 g NaOH ICS

  19. Solution PC4 2.0 L soln x 1000 mL = 2000 mL soln 1 L 12 % (m/v) NaOH = 12 g NaOH 100 mL NaOH soln 2000 mL x 12 g NaOH = 240 g NaOH 100 mL NaOH soln ICS

  20. Learning Check PC5 How many milliliters of 5 % (m/v) glucose solution are given if a patient receives 150 g of glucose? 1) 30 mL 2) 3000 mL 3) 7500 mL ICS

  21. Solution PC5 5% m/v factor 150 g glucose x 100 mL = 3000 mL 5 g glucose ICS

More Related