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Drive Beam Linac , surface building and equipment

Drive Beam Linac , surface building and equipment. B. Jeanneret, G. McMonagle August 2010 With material thanks to E.Jensen , R. Wegner , A. Aksoy , D. Siemaszko & D. Nisbet , J. Osborne, N. Baddams. parameters. Cell structure R. Wegner , E. Jensen, A, Aksoy , D. Schulte.

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Drive Beam Linac , surface building and equipment

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  1. Drive BeamLinac , surface buildingand equipment B. Jeanneret, G. McMonagle August 2010 Withmaterialthanks to E.Jensen, R. Wegner, A. Aksoy, D. Siemaszko & D. Nisbet, J. Osborne, N. Baddams

  2. parameters

  3. Cell structureR. Wegner, E. Jensen, A, Aksoy, D. Schulte • RF active section : 20 cells × 0.1m = 2m • Coupler, interconnect : 0.5 m • Quad, MBCO, BPM : 0.6 m • TOTAL : 3.1 m • May needadjustement ( Vacuum equip. for pressure p ~ 5 10-11 Torr, … ) 15 MW klystrons Acc. V/module 3.2 MV 819 cells / linac Total length 2540 m Plug-power for RF (2 linacs): 290 MW ( 0.115 MW/m) 3100 Linac 1

  4. Magnets – quadrupoles • N=819 Q, spaced by 3.1m for eachLinac (total Linaclength 2540m) • R = 3.7 10-2Ω, Imax = I0 = 414 A, pmax = 6.3 kW • Gradient must follow the beamenergyincrease • I(n) = nI0/N • Power schemesimilar to DECEL_Q advisable • Total power : P = Npmax/3 = 4 MW I(n) I0 = 414 A 1 (s=0) N=819 (s=2540m)

  5. Power & Cooling • Total plug power for RF : Ptot = 290 MW • 140 MW to beam150 MW to heat • Total power for magnets (Quad + Sol): 9 MW to heat • Total installed power : • Pinstalled = (1+ ε) × ( 290 + 9 ) • withε the 18kV conversion yield (seewith Daniel/Cesary) • Add for light, cranes, safetysystems, … • Total cooling power (tunnel & surf. Blg) : • Pcool = (1+ ε) × ( 150 + 9 )

  6. DB Linac, tunnel • Total lengthnow : 2540 m • conflictwith EHN1 •  move towards top of the drawing, seebelow Water cooling pipes, Cabletrays Loads 1200 3000 1000 1000 800 6000

  7. 2m DB Linac building Top view (half) 3.1m Width: 23.5m Height: 9m ? Length : 2540 m 0.75m 3m 5m 3m Klystrons are transported along the central path. A technical area without RF must beforeseenat crane extremities End view (half) 11.75m 3.5m ? 3m 1.5m 2.5m 4m 2m

  8. Top View of DB Linac xx • A small building isneeded for 18kV station ~ everyyy = 40 m ? • Size : xx by xx , xx = ? • Installed power 4.6 MW/40m xx Awaiting data From RF and EL ~yy 23000

  9. Top view of DB Linac buildings 2140 m 23 m 30 m Fixed point (beforedelayloops) 420 m Underground & surface (slide 6 & 7) Underground, Same section as in slide 6 (CDR, to berevised for TDR)

  10. Site implementation DB Linac (undergroud and surface) - Long segment : 2140 m - Short segment : 420 m Loop : underground - radius : 30 m Axis separation of the segments : - 30 m

  11. 500 GeVdelayedtransfer for the drive beam B.Jeanneret , July 2010

  12. Input data • Time delaybetween e+ & e- DB train : • The two sets of 5 trains each 240 ns are produced one after the otherwith a single Linac • Δt = 5 × 24 × 240 ns = 28800 ns Δ = 8640 m • The trains must besynchronouswhen passing along the end of the Main Linac

  13. Coming back to surface Case 1 G D C I H F TA • Case 1 : • e+ trains come first and go through : AFGHI-TA-IHGFBCD • e- trains go through : AFGHI • Case 2 : • e- trains come first and go through : ABCD-TA-DCBFGHI • e+ trains go through : ABCD r x From CR2 B A Blue : additionalbeam line Red : additional tunnel D,I : end of ML Case 2 G D C I H F x TA r From CR2 B A • AG = 770 • GH = 1449 • HI = CD = 25 (500GeV) • AC = 2117 • AB = 2r = 524 • TA = 146 • With y = AG+GH+AC+2*HI • x = (Δ + 2r – y –TA)/2 • x(case1) = x(case2) = 2316 m See ~/clic/CDR/500gev/bypath.sce

  14. Impact for hardware / through surface • Case 2 simpler • x / Lsector = 2316/877 = 2.64 sectors • one extra DB line to behoused in the main tunnel • Civ. Eng. : • one-quartercircle of surface tunnel to beadded • Line e+ down to tunnel : • wideenough to accomodate a 3rd beam line. • 1 additionnalturn-around , of type ‘DB’ • Additionalbeamlines: • 3909 m (AC-2r+x) of type ‘DB-LTL’ • 1 dedicatedturn-around , of type ‘DB’

  15. Use a by-patharound IP • D,I : end of ML (500 GeV) • e+ in D & e-in I : synchronous • Δdb = 8640 • ID = 2×1870 , TA = 146 • δbp = 14 • x = (Δdb - δbp - ID –TA)/2 = 2361 m • x / Lsector = 2361/877 = 2.70 sectors IP I D C x TA From CR2 A see :/Users/Bernard/clic/CDR/500gev/bypath_ugnd.sce

  16. Impact for hardware / underground by-path • x / Lsector = 2361/877 = 2.7 sectors • one extra DB line to behoused in the main tunnel • Civ. Eng. : • 374 m of tunnel to beadded for by-path • 1 additionnalturn-around , of type ‘DB’ • Additionalbeamlines: • 3740 m ( DI ) of type ‘DB-LTL’ • 1 dedicatedturn-around , of type ‘DB’ • Beamlines not needed : • Surface loop & descent down (2460 m) • Advantage : disconnectedfrom surface changes for Main Beam

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