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Understanding Alcoholism and Profession Association through Chi-Square Test in 1st Semester of 2007/2008

Explore the Contingency Table of Alcoholism versus Profession using Chi-Square Test, determining independence or dependence. Calculate observed cell frequency, rejection region, and degrees of freedom. Reject the null hypothesis based on critical chi-square values.

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Understanding Alcoholism and Profession Association through Chi-Square Test in 1st Semester of 2007/2008

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  1. Chi Square (2) Test 1st Semester 2007/2008

  2. Contingency Table of Alcoholism versus Profession H0 Independent H1  Dependent

  3. Equation O  Observed cell frequency E  (row total x column total) / grand total Df  (# of rows -1) x (# of columns – 1) Rejection Region 2  2 Reject H0 !!!

  4. E = (row total x column total)/grand totalEclergy&alcoholic = (233 x 300) / 1200 = 58,25

  5. cclergy&alcoholic(O-E)2/E = (32-58,25)2 / 58,25 = 11,83

  6. Df  (4 -1) x (2 – 1) = 3   5%  0,05 2 7,81 Rejection Region 2  2 20,60  7,81  Reject H0  Dependent

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