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Homework Review. Example 1 Solving by Completing the Square when a ≠ 1. Solve the following equation by completing the square: Step 1: Divide each side by the coefficient of x 2 . Step 2: Rewrite so all terms containing x are on one side. Example 1 Continued.
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Example 1 Solving by Completing the Square when a ≠ 1 Solve the following equation by completing the square: Step 1: Divide each side by the coefficient of x2. Step 2: Rewrite so all terms containing x are on one side
Example 1 Continued Step 3: Find the term that completes the square on the left side of the equation. Add that term to both sides.
Example 1 Continued Step 4: Factor the perfect square trinomial on the left side of the equation. Simplify the right side of the equation. Step 5: Take the square root of each side.
Example 1 Continued Step 6: Solve for x.
5x2 = 6x + 8 You Try: Solving When a≠0 2x2 + x = 6
Problem-Solving 3(x + 2)(x – 5) = 54 3(x2 – 3x – 10) = 54 (x + 2) cm The volume of the box below is 54cm3. Find the dimensions of the box by completing the square. x2 – 3x – 10 = 18 x2 – 3x = 28 (x – 5) cm 3 cm Since x = 7, the dimensions are 9 cm by 3 cm by 2 cm.
Problem-Solving The height, h, in feet of a kicked soccer ball can be modeled by the function h(t) = –16t2 + 32t + 1 where t is seconds. On its way down, the ball bounces off the cross bar of the goal, which is 8 feet above the ground. To the nearest tenth, when did the ball hit the cross bar? –16t2 + 32t + 1 = 8 –16t2 + 32t = 7 –16(t2 – 2t) = 7 After 1.75 seconds, the ball hit the cross bar.
Problem-Solving In a track and field event, a contestant made a throw in the shot put that can be modeled by y = –0.02x2 + x + 6 where x is the shot put’s horizontal distance in feet and y is the corresponding height in feet. How long was the throw? Round your answer to the nearest tenth. –0.02x2 + x + 6 = 0 x2 – 50x – 300 = 0 x2 – 50x = 300 The shot put traveled a distance of 55.4 feet.