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Unit 1 Measure and Classify Angles. B. 1. A. C. Two different rays with the same initial point. Measured in degrees. Angle:. A ,. BAC ,. CAB,. 1. Common initial point, where rays meet. pt. A. vertex. side. The rays of the angle. side. Point inside an angle.
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Unit 1 Measure and Classify Angles
B 1 A C Two different rays with the same initial point. Measured in degrees. Angle: A, BAC, CAB, 1
Common initial point, where rays meet pt. A vertex side The rays of the angle side
Point inside an angle Pt. D is in the interior of BAC D Point outside an angle Pt. E is in the exterior of BAC E
A Angle more than 0°, but less than 90° mA = 50° Angle that measures 90° mR = 90° R Angle more than 90°, but less than 180° mO = 110° O Angle that measures 180° mS = 180° S
Angle Bisector: Ray that cuts an angle in half to make 2 congruent angles QS bisects PQR P S PQS SQR mPQS = mSQR Q R Note: To name an angle use “ ”, but when stating its measure use “_______”. m
Adjacent angles: Two angles that share a common side and vertex 2 1 1 is adjacent to 2
Angle Addition Postulate: If you add two adjacent angles, it totals to get their sum. C A B D mABC + mCBD = mABD
1. Give three names for the angle shown, then name the vertex and sides. DEF Pt. E FED E
1. Give three names for the angle shown, then name the vertex and sides. QVS Pt. V SVQ V
2. Classify the angle as acute, right, obtuse or straight. mA = 115° obtuse
2. Classify the angle as acute, right, obtuse or straight. mA = 90° right
2. Classify the angle as acute, right, obtuse or straight. mA = 85° acute
2. Classify the angle as acute, right, obtuse or straight. mA = 180° straight
4. Find the indicated measure. mPRS = 81+42 mPRS = 123°
4. Find the indicated measure. mWXZ = 90 – 26 = mWXZ = 64°
mNRP + mPRQ = mNRQ 8x + 7 + 4x – 1 = 78 12x + 6 = 78 12x = 72 x = 6 mPRQ = 4(6) – 1 mPRQ = 24 – 1 mPRQ = 23°
mADB + mBDC = mADC 11x – 7 + 5x – 3 = 118 16x – 10 = 118 16x = 128 x = 8 mADB = 11(8) – 7 mADB = 88 – 7 mADB = 81°
6. Find each indicated angle. 15° 90° 90° 75° 15°
Find each indicated angle. 67° 106° 74° 157° c = 180-90-23 = 67° a = 180-74 = 106° d = 180-23 = 157° b = 180-106 = 74°
5x + 2 = 7x – 6 2 = 2x – 6 8 = 2x 4 = x mABC = 20+2 +28-6 = 44° 5(4)+2 + 7(4)-6 =
5x + 13 = 9x – 23 13 = 4x – 23 36 = 4x 9 = x mABC = 45+13+81-23 = 116° 5(9)+13 + 9(9)-23 =
HW Problem # 38 53° 37°