180 likes | 337 Views
SIMPLE PENDULUM. SIMPLE PENDULUM. SIMPLE PENDULUM. SIMPLE PENDULUM. SIMPLE PENDULUM. ENERGY. U = mgy = mg ( L – L cos q ) E = K + U = ½ mv ² + mg ( L – L cos q ) E = mg ( L – L cos q m ) mg ( L – L cos q m ) = ½ mv ²
E N D
ENERGY • U = mgy = mg(L – L cos q) • E = K + U =½ mv² + mg(L – L cos q) • E = mg(L – L cos qm) • mg(L – L cos qm) =½ mv² • + mg(L – L cos q) • – gL cos qm =½ v² – gL cos q
ENERGY • ½ v² = gL cos q – gL cos qm • v² = 2gL (cos q – cos qm) and s = L q
POTENTIAL ENERGY • Choose U = 0 at r = ¥
Conservation ofMechanical Energy • When dropped from • r = R • with v0 = 0.