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Diffusion and Osmosis

Diffusion and Osmosis. Diffusion and Osmosis Overview. You will investigate diffusion and osmosis in a model membrane system You will investigate the effect of solute concentration on water potential as it relates to living plants. Concentration Effect. Molarity. C 6 H 12 O 6 = glucose

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Diffusion and Osmosis

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  1. Diffusion and Osmosis

  2. Diffusion and Osmosis Overview • You will investigate diffusion and osmosis in a model membrane system • You will investigate the effect of solute concentration on water potential as it relates to living plants.

  3. Concentration Effect

  4. Molarity • C6H12O6 = glucose • Sucrose = 2 glucose • C6H12O6 + C6H12O6 = C6H12O6 - H2O = C12H22O11 so • Using the periodic table, you can calculate GFM of sucrose (342g)

  5. So to make 500 ml of solution……. • 0.0 Molar = 342g x 0 x .5 • 0.2 M = 342 x .2 x .5 • etc

  6. Prepare dialysis bags…… • Add sucrose solutions to bags • Mass carefully • Place in distilled water for 30 minutes • Re-mass • Calculate the % change in mass

  7. Final Mass-Initial MassInitial Mass To Calculate the % change in mass: X 100

  8. Period 4 Lab 1B Data

  9. Period 5 Lab 1B Data

  10. Period 4 Lab 1C Data

  11. Period 5 Lab 1C Data

  12. Lab 1C: Ideal Class Data

  13. LinearFit for: Data Set Percent Change in Mass

  14. Water Potential In Potato Cells • Osmosis is a special type of diffusion. It is the movement of water molecules through a selectively permeable membrane from a region of higher water potential to an area of lower water potential • Water potential is the measure of free energy of water in a solution • Water always moves to a morenegative water potential.

  15. Water Potential • = Yp + Ys Where there is no % change in mass, the solution in the beaker has the same water potential as the potato cells. (Y = Yp + Ys) = (Y = Yp + Ys) Beaker Potato Yp = 0 (open beaker) so Y = Ys

  16. To CalculateYs • See page 13 of the lab Ys = -iCRT i = Ionization constant (sucrose is 1.0 because it does not ionize). C = Molar Concentration (from line of best fit where the line crosses the x axis) R = Pressure Constant (0.0831 liter bars/mole °K T = Temperature °K (273 + °C)

  17. So lets say the line of best fit crosses the x axis at 0.36…….. Ys = -iCRT Ys = -(1.0)(0.36 mole/liter)(0.0831 liter bar/mole ° K)(295 ° K) -8.83 bars This equals the entire Y of the cell

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