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PHYSICS PROBLEMS MIRRORS AND LENSES

PHYSICS PROBLEMS MIRRORS AND LENSES. Object Beyond 2f 1/d o + 1/d i = 1/f 1/32 + 1/d i = 1/8 d i = + 10.67 + real on right Between f and 2f. 1. d o = +32 cm f = 8 cm 2f = 16 cm convex lens converging lens.

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PHYSICS PROBLEMS MIRRORS AND LENSES

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  1. PHYSICS PROBLEMS MIRRORS AND LENSES

  2. Object Beyond 2f 1/do + 1/di = 1/f 1/32 + 1/di = 1/8 di = + 10.67 + real on right Between f and 2f 1. do = +32 cm f = 8 cm 2f = 16 cm convex lens converging lens m = - di/do m = - 10.67 / 32 m = -0.33 - inverted <1 smaller 2. ho = +2.25 mm d0 = +8.5 cm f = 5.5 cm 2f = 11 cm convex lens converging lens Object Between f and 2f 1/do + 1/di = 1/f 1/8.5 + 1/di = 1/5.5 di = + 15.58 + real on right Beyond 2f m = - di/do m = - 15.58 / 8.5 m = -1.83 - inverted >1 larger 3. f = 25mm = 2.5 cm 2f = 5 cm convex lens converging lens An object and an image are the same size at 2f. The object must be placed at 5 cm and the image will be the same size at 5 cm. The image is real and inverted. m = - di/do -2 = - di / 7 di = +14 + real on right 4. m = -2 (inverted twice as large) do = +7 cm 1/do + 1/di = 1/f 1/7+ 1/14 = 1/f f= + 4.67 + convex (converging) lens Lenses Answers are everything in RED

  3. Object Between f and lens 1/do + 1/di = 1/f 1/4 + 1/di = 1/6 di = - 12 cm - Virtual Behind lens 5. do = +4 cm f = 6 cm 2f = 12 cm convex lens converging lens m = - di/do m = - (-12) / 4 m = +3 + erect >1 larger Object Between f and lens 1/do + 1/di = 1/f 1/6 + 1/di = 1/20 di = - 8.57 cm - Virtual Behind lens 6. do = +6 cm f = 20 cm 2f = 40 cm convex lens converging lens m = - di/do m = - (-8.57) / 6 m = +1.43 + erect >1 larger 7. do = +3.4 cm ho = 2 cm f = 12 cm 2f = 24 cm convex lens converging lens Object Between f and lens 1/do + 1/di = 1/f 1/3.4 + 1/di = 1/12 di = - 4.74 cm - Virtual Behind lens m = - di/do m = - (-4.74) / 3.4 m = +1.39 + erect >1 larger m = hi / ho + 1.39 = hi / 2 hi = 2.78 cm

  4. m = - di/do 4 = - di / 3.5 di = - 14 - Virtual Behind lens 8. m = +4 (erect four times) do = +3.5 cm 1/do + 1/di = 1/f 1/3.5+ 1/-14 = 1/f f= + 4.67 + convex (converging) lens Object Beyond 2f 1/do + 1/di = 1/f 1/72.5 + 1/di = 1/25.5 di = + 39.34 cm + real on right Between f and 2f 9. do = +72.5 cm f = 25.5 cm 2f = 51 cm convex lens converging lens m = - di/do m = - 39.34 /72.5 m = -.54 - inverted <1 smaller 10. do = 10 cm f = 5 cm If d0 is 2f (2*5 = 10) then di will also be at 2f 10 cm The image will be real on right inverted and the same size convex lens converging lens 11. do = +22 cm ho = 3 cm di = + 11cm convex lens converging lens m = - di/do m = - 11 / 22 m = -0.50 - inverted <1 smaller m = hi / ho -0.50 = hi / 3 hi = -1.5 cm

  5. di = 3.8 cm hi = .9 cm C F MIRROR HANDOUT H2 1 -5 AP 1 - 9 1. 2F = C 2(10) = 20 cm 2. 2F = C 2F = 150 F = 75 cm will collect at focal point 3. F = 3 cm Collect at focal point Diagrams must be drawn to scale. 1cm = 1cm C = radius = 6 cm Calculated 1/do+ 1/di = 1/f 1/12 + 1/di = 1/3 di = 4 cm hi/ho = -di/do hi/2.4 = - 4/12 hi = -.8 cm = -8mm - means inverted do = 12 cm

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