90 likes | 245 Views
7.5 Applications to Physics and Engineering. a Find k :. b. How much work would be needed to stretch the spring 3m beyond its natural length?. Review: Hooke’s Law:. A spring has a natural length of 1 m . A force of 24 N stretches the spring to 1.8 m .
E N D
a Find k: b How much work would be needed to stretch the spring 3m beyond its natural length? Review: Hooke’s Law: A spring has a natural length of 1m. A force of 24N stretches the spring to 1.8 m.
If we add up all these small bits of work we get: Over a very short distance, even a non-constant force doesn’t change much, so work becomes:
2 ft 10 ft A conical tank is filled to within 2 ft of the top with salad oil weighing 57 lb/ft3. How much work is required to pump the oil to the rim? 10 ft Consider one slice (slab) first:
2 ft 10 ft A conical tank if filled to within 2 ft of the top with salad oil weighing 57 lb/ft3. How much work is required to pump the oil to the rim? 10 ft
2 ft 10 ft A conical tank if filled to within 2 ft of the top with salad oil weighing 57 lb/ft3. How much work is required to pump the oil to the rim? 10 ft
What is the force on the bottom of the aquarium? 2 ft 3 ft 1 ft
All the other water in the pool doesn’t affect the answer! If we had a 1 ft x 3 ft plate on the bottom of a 2 ft deep wading pool, the force on the plate is equal to the weight of the water above the plate. density depth area pressure
0 2 ft 2 3 ft What is the force on the front face of the aquarium? 2 ft Depth (and pressure) are not constant. If we consider a very thin horizontal strip, the depth doesn’t change much, and neither does the pressure. 3 ft 1 ft depth density area