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COMBUSTION of PROPANE

COMBUSTION of PROPANE. 1. What does the reaction involve? (reactants and products). Reaction needs to be balanced. COMBUSTION of PROPANE. 2. Envision the “structural formulas” for the reactants and the products (from your knowledge of Lewis structures). COMBUSTION of PROPANE.

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COMBUSTION of PROPANE

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  1. COMBUSTION of PROPANE 1. What does the reaction involve? (reactants and products) Reaction needs to be balanced

  2. COMBUSTION of PROPANE 2. Envision the “structural formulas” for the reactants and the products (from your knowledge of Lewis structures)

  3. COMBUSTION of PROPANE 3. List the bonds broken (between which atoms) bonds within the reactants are expected to be broken In C3H8 2 x C-C bonds 8 x C-H bonds In O2 1 x O=O bond

  4. COMBUSTION of PROPANE The numbers and types of bonds within the reactants which are expected to be broken are… In C3H8 2 x C-C bonds 8 x C-H bonds In O2 1 x O=O bond However, we need to check the coefficient in front of each reactant (look at the balanced equation) There are 5 moles of O2 reacting with each mole of propane Therefore, in 5 x O2 5 x O=O bonds

  5. COMBUSTION of PROPANE 4. Find the Bond Dissociation Energies (BDE) associated for each bond (from Table 4.4) BDE’s for C-C bonds: 356 kJ/mole C-H bonds: 436 kJ/mole O=O bonds: 498 kJ/mole

  6. COMBUSTION of PROPANE Remember, there are 2 x C-C bonds 8 x C-H bonds 5 x O=O bonds (after balancing the equation) Here is the energy required to break all the bonds mentioned above: 2 x 356 kJ/mole = 712 kJ 8 x 436 kJ/mole = 3488 kJ 5 x 498 kJ/mole = 2490 kJ TOTAL: 6690 kJ

  7. COMBUSTION of PROPANE 5. We now need to look at the products and the new bonds formed as a result of the reaction These are the new bonds which are formed

  8. COMBUSTION of PROPANE new bonds formed within the products In CO2 2 x C=O bonds In H2O2 x O-H bonds However, we need to check the coefficient in front of each reactant (look at the balanced equation) There are 3 moles of CO2 being formed (for each mole of propane) and 4 moles of H2O therefore In 3 x CO23 x 2 x C=O bonds In 4 x H2O 4x 2 x O-H bonds

  9. COMBUSTION of PROPANE • 6. Find the Bond Dissociation Energies (BDE) associated for each bond being formed • (from Table 4.4) BDE’s for C=O bonds: 803 kJ/mole O-H bonds: 467 kJ/mole

  10. COMBUSTION of PROPANE Remember, there are 3 x 2 x C=O bonds 4 x 2 x O-H bonds being formed (after balancing the equation) Here is the energy released when all the bonds mentioned above are formed: 6 x 803 kJ/mole = 4818 kJ 8 x 467 kJ/mole = 3736 kJ TOTAL: 8554 kJ

  11. COMBUSTION of PROPANE 7. Subtract the total energy released from the total energy required to break the bonds to determine the heat of reaction, DH DH = 8554 kJ - 6690 kJ =1864 kJ Let’s focus on the units now: This is 1864 kJ per mole of propane, C3H8 undergoing complete combustion

  12. COMBUSTION of PROPANE 8. What if we wishto determine the heat of reaction, DH, per gram of propane, C3H8 undergoing complete combustion In 1 mole of C3H8 there are 44 g of C3H8 Therefore, the DH value we calculated previously is associated with 44 g of C3H8 DH = 1864 kJ per 44 g of propane undergoing complete combustion

  13. COMBUSTION of PROPANE If 44 g of C3H8 releases 1864 kJ of energy, then 1.0 g of C3H8 will release 1/44 of that amount DH = 1864/44 kJ per 1.0 g of propane = 42.4 kJ/g of propane viewing the following units together might further clarify the type of calculation involved in converting the amount of energy from per mole to per gram

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