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Choctaw High School Algebra I EOI Review. PowerPoint Overview Unit 1 Lesson 1.1 – Simplifying Expressions. To simplify an algebraic expressions, you need to combine the like terms. Like terms have the same variables with the same exponents.
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Choctaw High School Algebra I EOI Review PowerPoint OverviewUnit 1 Lesson 1.1 –Simplifying Expressions
To simplify an algebraic expressions, you need to combine the like terms. Like terms have the same variables with the same exponents. If two terms are like terms, then only their coefficients may differ. Once you find all the like terms, you can combine them by adding or subtracting the coefficients only. Simplifying Expressions
An algebraic expression is a collection of real numbers, variables, grouping symbols and operation symbols. Here are some examples of algebraic expressions. Algebraic Expressions
The terms of the expression are separated by addition. There are 3 terms in this example and they are . The coefficientof a variable term is the real number factor. The first term has coefficient of 5. The second term has an unwritten coefficient of 1. The last term , -7, is called a constant since there is no variable in the term. Consider the example:
Let’s begin with a review of two important skills for simplifying expression, using the Distributive Property and combining like terms. Then we will use both skills in the same simplifying problem.
a ( b + c ) = ba + ca Distributive Property To simplify some expressions we may need to use the Distributive Property Do you remember it? Distributive Property
Examples Example 1: 6(x + 2) Distribute the 6. 6 (x + 2) = x(6) + 2(6) = 6x + 12 Example 2: -4(x – 3) Distribute the –4. -4 (x – 3) = x(-4) –3(-4) = -4x + 12
Try the Distributive Property on -7 ( x – 2 ) . Be sure to multiply each term by a –7. -7 ( x – 2 ) = x(-7) – 2(-7) = -7x + 14 Notice when a negative is distributed all the signs of the terms in the ( )’s change. Practice Problem
Examples with 1 and –1. Example 3: (x – 2) = 1( x – 2 ) = x(1) – 2(1) = x - 2 Notice multiplying by a 1 does nothing to the expression in the ( )’s. Example 4: -(4x – 3) = -1(4x – 3) = 4x(-1) – 3(-1) = -4x + 3 Notice that multiplying by a –1 changes the signs of each term in the ( )’s.
Like terms are terms with the same variables raised to the same power. Hint: The idea is that the variable part of the terms must be identical for them to be like terms. Like Terms
Examples Like Terms 5x , -14x -6.7xy , 02xy The variable factors are identical. Unlike Terms 5x , 8y The variable factors are not identical.
Recall the Distributive Property a (b + c) = b(a) +c(a) To see how like terms are combined use the Distributive Property in reverse. 5x + 7x = x (5 + 7) = x (12) = 12x Combining Like Terms
All that work is not necessary every time. Simply identify the like terms and add their coefficients. 4x + 7y – x + 5y = 4x – x + 7y +5y = 3x + 12y Example
This example requires both the Distributive Property and combining like terms. 5(x – 2) –3(2x – 7) Distribute the 5 and the –3. x(5) - 2(5) + 2x(-3) - 7(-3) 5x – 10 – 6x + 21 Combine like terms. - x+11 Both Skills
Distribute. Simplifying Example
Distribute. Simplifying Example
Distribute. Combine like terms. Simplifying Example
Distribute. Combine like terms. Simplifying Example