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Chi-Square Practice Problems

Chi-Square Practice Problems. Answer Key. Problem # 2. X 2 = (161-150) 2 + (139-150) 2 150 150 X 2 = (11) 2 + (11) 2 150 150 X 2 = 121 + 121 150 150 X 2 = 0.81 + 0.81

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Chi-Square Practice Problems

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  1. Chi-Square Practice Problems Answer Key

  2. Problem # 2 X2 = (161-150)2 + (139-150)2 150 150 X2 = (11)2 + (11)2 150 150 X2 = 121 + 121 150 150 X2 = 0.81 + 0.81 X2 = 1.62

  3. Problem # 3 X2 = (112-105)2 + (195-210)2 + (113 – 105)2 105 210 105 X2 = (7)2 + (15)2 + (8)2 105 210 105 X2 = 49 + 225 + 64 105 210 105 X2 = 0.47 + 1.07 + 0.61 X2 = 2.15

  4. Problem # 4 X2 = (315-312.75)2 + (108-104.25)2 + (101-104.25)2 + (32 – 34.75)2 312.75 104.25 104.25 34.75 X2 = (2.25)2 + (3.75)2 + (-3.25)2 + (-2.75)2 312.75 104.25 104.25 34.75 X2 = 5.06 + 14.06 + 10.56 + 7.56 312.75 104.25 104.25 34.25 X2 = 0.02 + 0.13 + 0.10 + 0.22 X2 = 0.47

  5. Problem # 5 X2 = (91-100)2 + (111-100)2 + (93-100)2 + (105 – 100)2 100 100 100 100 X2 = (9)2 + (11)2 + (-7)2 + (-5)2 100 100 100 100 X2 = 81 + 121 + 49 + 25 100 100 100 100 X2 = 0.81 + 1.21 + 0.49 + 0.25 X2 = 2.76

  6. Degrees of Freedom Suppose we have the following situation: ___ + ___ = 20 ab I can “plug” any positive integer into a. Once I have “plugged” in an integer, then the integer that goes into b is set (no choice) If I have ___ + ___ + ___ = 20 a b c I can “plug” any positive integer into a & b, but once I do, the value of c is set (no choice). Thus, degrees of freedom is n-1, where n = number of groups

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