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BELLWORK

BELLWORK. ANSWER. J. Boyle’s Law 11.2 PPT. What is Boyle’s Law?. Boyle’s Law states that when a gas is under pressure it takes up less space:

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BELLWORK

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  1. BELLWORK

  2. ANSWER • J

  3. Boyle’s Law11.2 PPT

  4. What is Boyle’s Law? • Boyle’s Law states that when a gas is under pressure it takes up less space: • Boyles Law tells us about the relationship between the volume of a gas and its pressure at a constant temperature. The higher the pressure, the smaller the volume.

  5. BOYLE’S LAW VIDEO

  6. Volume vs. PressureInverse Relationship

  7. Sample Problem: • A deep sea diver is working at a depth where the pressure is 3.0 atmospheres. He is breathing out air bubbles. The volume of each air bubble is 2 cm3. At the surface the pressure is 1 atmosphere. What is the volume of each bubble when it reaches the surface?

  8. Figure out which variables the problems deals with (Volume and Pressure only) Use the Combined Gas Law Formula (Refer to reference sheet) Ignore the Temperature in the Formula P1V1= P2V2 T1 T2 BOYLE’S LAW

  9. How we work this out: • This is the formula we are going to use: (Derived from the Combined Gas Law on your reference page) • Formula first: P1 x V1 = P2 x V2 (Refer to reference Page) • Given:= P1 = 3.0 atm • V1 = 2 cm3 • P2 = 1.0 atm • Unknown: V2

  10. Here’s what you should have calculated P1 x V1 = P2 x V2 3 atm x 2 cm3 = 1 atm x V2 6 = 1 (V2) V2= 6 cm3

  11. Classwork • Boyles’s Law Worksheet

  12. Charles’ Law The Temperature-Volume Relationship

  13. Charles’ Law • French chemist Jacques Charles discovered that the volume of a gas at constant pressure changes with temperature. • Temperature and volume are directly related……As the temperature of the gas increases, so does its volume, and vice versa

  14. VIDEO

  15. V T Volume vs. TemperatureDirect Relationship

  16. Example • If the temperature of a given amount of gas is doubled, for example, its volume will also double (as long as pressure remains unchanged).

  17. Charles’ Law Example Problem: A sample of neon gas occupies a volume of 752 mL at 25°C. What volume will the gas occupy at 50°C if the pressure remains constant? Given: V1 = 752 mL T1 = 25°C + 273 = 298K T2 = 50°C + 273 = 323K

  18. Charles’ Law • Determine which variables are in the problem. • Delete the variable that is not in the problem. (Pressure) That means that pressure remains constant. • Use the Combined Gas Law to extrapolate the right equation to solve this problem (reference sheet) P1V1= P2V2 T1 T2

  19. Equation Used: V1 = V2 T1 T2 752 mL = V2 298 K 323K 298K = 242896mL V2 = 815 mL

  20. Gay-Lussac’s Law

  21. What is Gay-Lussac’s Law? • Gay-Lussac’s Law states that when a gas is under constant volume, there is a direct relationship between temperature and pressure. • The higher the temperature, the higher the pressure.

  22. Gay-Lussac’s Law: P and T Gay-Lussac’s law states that • The pressure exerted by a gas is directly related to the Kelvin temperature. • V is constant. • An increase in temperature increases the pressure of a gas. 22

  23. PRESSURE VS. TEMP

  24. Calculation with Gay-Lussac’s Law A gas has a pressure at 2.0 atm at 18 ˚C. What is the new pressure when the temperature is increased to 62 ˚C? Which variable is constant? 24

  25. Used the Combined Gas Law When you have problems that give you volume and pressure. Delete Volume in the Equation P1 V1= P2 V2 T1 T2 Gay-Lussac’s Law

  26. This formula is used when the volume is constant. P1 = P2 T1 T2 Gay-Lussac’s Law

  27. CLASSWORK • Chapter 11 Wksht #1

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