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Applied Le Chatelieir's Principle Lesson 4

Applied Le Chatelieir's Principle Lesson 4. Lab 19A Le Chatelier’s Principle Copy the five Equilibrium Equations into your lab handout. Part I. Thymol Blue (blue) + H + ⇌ Thymol Blue (yellow). Part II. Fe 3+ (aq) + SCN - (aq) ⇌ FeSCN 2+ (aq) yellow brown

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Applied Le Chatelieir's Principle Lesson 4

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  1. Applied Le Chatelieir's Principle Lesson 4

  2. Lab 19A Le Chatelier’s Principle Copy the five Equilibrium Equations into your lab handout

  3. Part I Thymol Blue (blue) + H+ ⇌ Thymol Blue (yellow)

  4. Part II Fe3+(aq) + SCN-(aq)⇌ FeSCN2+(aq) yellowbrown Fe3+(aq) + 3OH-→Fe(OH)3(s)

  5. Part III Co(H2O)62+ + 2Cl- ⇌Co(H2O)4Cl22- + 2H2O(l) pinkblue

  6. Part IV Energy+ 2CrO42- + 2H+ ⇌ Cr2O72- + H2O(l) yellow orange Ba2+ + CrO42-→ BaCrO4(s)

  7. Part V Cu(H2O)42+ + 2NH3⇌ Cu(OH)2(s) + 2NH4+ + 2H2O light blue powder blue Cu(OH)2(s)+ 4NH3 ⇌ Cu(NH3)42+ + 2OH- powder blue violet

  8. Application of Le Chatelier’s Principle Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange Know the following: Any acid is H+ Any base is OH- Acids react with basesH+ + OH-→ H2O(l) Stress Shift [CrO42-] [Cr2O72-] colour  Add H+ Add CrO42- Add Cr2O72-

  9. Application of Le Chatelier’s Principle Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange Know the following: Any acid is H+ Any base is OH- Acids react with basesH+ + OH-→ H2O(l) Stress Shift [CrO42-] [Cr2O72-] colour  Add H+ Add CrO42- Add Cr2O72-

  10. Application of Le Chatelier’s Principle Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange Know the following: Any acid is H+ Any base is OH- Acids react with basesH+ + OH-→ H2O(l) Stress Shift [CrO42-] [Cr2O72-] colour  Add H+ Add CrO42- Add Cr2O72-

  11. Application of Le Chatelier’s Principle Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange Know the following: Any acid is H+ Any base is OH- Acids react with basesH+ + OH-→ H2O(l) Stress Shift [CrO42-] [Cr2O72-] colour  Add H+ right decrease increase orange Add CrO42- Add Cr2O72-

  12. Application of Le Chatelier’s Principle Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange Know the following: Any acid is H+ Any base is OH- Acids react with basesH+ + OH-→ H2O(l) Stress Shift [CrO42-] [Cr2O72-] colour  Add H+ right decrease increase orange Add CrO42- right increase increase ? Add Cr2O72-

  13. Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange Know the following: Any acid is H+ Any base is OH- Acids react with basesH+ + OH-→ H2O(l) Stress Shift [CrO42-] [Cr2O72-] colour  Add H+ right decrease increase orange Add CrO42- right increase increase ? Add Cr2O72- left increases increases ?

  14. Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange Acids react with basesH+ + OH-→ H2O(l) Stress Shift [CrO42-] [Cr2O72-] colour 

  15. Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange Acids react with basesH+ + OH-→ H2O(l) Stress Shift [CrO42-] [Cr2O72-] colour  Add NaOH

  16. Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange Acids react with basesH+ + OH-→ H2O(l) NaOH → Na+ + OH- Stress Shift [CrO42-] [Cr2O72-] colour  Add NaOH

  17. Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange Acids react with basesH+ + OH-→ H2O(l) NaOH → Na+ + OH- spectator ion stress ion-lowers H+ Stress Shift [CrO42-] [Cr2O72-] colour  Add NaOH

  18. Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+⇄ Cr2O72- + H2O(l) yellow orange Acids react with basesH+ + OH-→ H2O(l) NaOH → Na+ + OH- spectator ion stress ion-lowers H+ Stress Shift [CrO42-] [Cr2O72-] colour  Add NaOH left increases decreases yellow

  19. Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange BaCrO4 has low solubility BaCr2O7 has high solubility Stress Shift [CrO42-] [Cr2O72-] colour 

  20. Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange BaCrO4 has low solubility BaCr2O7 has high solubility Stress Shift [CrO42-] [Cr2O72-] colour  Ba(NO3)2

  21. Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange BaCrO4 has low solubility- Ba2+ reacts with CrO42- BaCr2O7 has high solubility- no reaction Ba(NO3)2→ Ba2+ + 2NO3- Stress Shift [CrO42-] [Cr2O72-] colour  Ba(NO3)2

  22. Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange BaCrO4 has low solubility BaCr2O7 has high solubility Ba(NO3)2→ Ba2+ + 2NO3- stress spectator Stress Shift [CrO42-] [Cr2O72-] colour  Ba(NO3)2

  23. Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange ↓ Ba2+ reacts with this ion BaCrO4 has low solubility BaCr2O7 has high solubility Ba(NO3)2→ Ba2+ + 2NO3- stress spectator Stress Shift [CrO42-] [Cr2O72-] colour  Ba(NO3)2

  24. Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange ↓ Ba2+ reacts with this ion BaCrO4 has low solubility BaCr2O7 has high solubility Ba(NO3)2→ Ba2+ + 2NO3- stress spectator Stress Shift [CrO42-] [Cr2O72-] colour  Ba(NO3)2 left decreases decreases yellow

  25. Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange Stress Shift [CrO42-] [Cr2O72-] colour  HCl

  26. Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange HCl → H+ + Cl- Stress Shift [CrO42-] [Cr2O72-] colour  HCl

  27. Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange HCl → H+ + Cl- stress spectator Stress Shift [CrO42-] [Cr2O72-] colour  HCl

  28. Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ ⇄ Cr2O72- + H2O(l) yellow orange HCl → H+ + Cl- stress spectator Stress Shift [CrO42-] [Cr2O72-] colour  HCl right decreases increases orange

  29. Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Cl- ⇄ Co(H2O)4Cl22- + 2H2O(l) pinkblue Stress stress ion spectator ion shift colour  HCl

  30. Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Cl- ⇄ Co(H2O)4Cl22- + 2H2O(l) pinkblue HCl → H+ + Cl- Stress stress ion spectator ion shift colour  HCl

  31. Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Cl- ⇄ Co(H2O)4Cl22- + 2H2O(l) pinkblue HCl → H+ + Cl- spectator stress Stress stress ion spectator ion shift colour  HCl

  32. Application of Le Chatelier’s Principle- 2 Co(H2O)62+ + 2Cl- ⇄ Co(H2O)4Cl2 + 2H2O(l) pinkblue HCl → H+ + Cl- spectator stress Stress stress ion spectator ion shift colour  HCl Cl- H+ right blue

  33. Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Cl- ⇄ Co(H2O)4Cl22- + 2H2O(l) pinkblue Stress stress ion spectator ion shift colour  Increase temperature

  34. Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Cl- ⇄ Co(H2O)4Cl22- + 2H2O(l) pinkblue Stress stress ion spectator ion shift colour  Increase temperature

  35. Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Cl- ⇄ Co(H2O)4Cl22- + 2H2O(l) pinkblue Stress stress ion spectator ion shift colour  ↑ temp none none right blue

  36. Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Cl- ⇄ Co(H2O)4Cl22- + 2H2O(l) pinkblue Stress stress ion spectator ion shift colour  AgNO3

  37. Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Cl- ⇄ Co(H2O)4Cl22- + 2H2O(l) pinkblue AgNO3 →Ag+ + NO3- Stress stress ion spectator ion shift colour  AgNO3

  38. Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Cl- ⇄ Co(H2O)4Cl22- + 2H2O(l) pinkblue AgNO3 →Ag+ + NO3- ↑ stress- low solubility (data book-4) with Cl- Stress stress ion spectator ion shift colour  AgNO3

  39. Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Cl- ⇄ Co(H2O)4Cl22- + 2H2O(l) pinkblue AgNO3 →Ag+ + NO3- ↑ stress- low solubility (data book-4) with Cl- Stress stress ion spectator ion shift colour  AgNO3Ag+ NO3- left pink

  40. Here is a the first question from your lab. I will give you a good answer so that you understand the level of detail that is required in the response 1. Explain the colour changes observed when Fe(NO3)3, KSCN, and NaOH were added to the thiocyanatoiron equilibrium system. Start by writing the equilibrium equation. Fe3+(aq) + SCN-(aq)⇄ Fe(SCN)2+(aq) yellowbrown Adding Fe(NO3)3increases the [Fe3+] and causes the reaction to shift right and turn brown. Adding KSCN increases the [SCN-] and causes the reaction to shift right and turn brown. Adding NaOHincreases the [OH-] which reacts with Fe3+, lowering the [Fe3+] causing the equilibrium to shift left and turn yellow.

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