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Exponential and Logarithmic Equations and Inequalities. 4-5. Warm Up. Lesson Presentation. Lesson Quiz. Holt McDougal Algebra 2. Holt Algebra 2. Objectives. Solve exponential and logarithmic equations and equalities. Solve problems involving exponential and logarithmic equations.

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  1. Exponential and Logarithmic Equations and Inequalities 4-5 Warm Up Lesson Presentation Lesson Quiz Holt McDougal Algebra 2 Holt Algebra 2

  2. Objectives Solve exponential and logarithmic equations and equalities. Solve problems involving exponential and logarithmic equations.

  3. An exponential equation is an equation containing one or more expressions that have a variable as an exponent. To solve exponential equations: • Try writing them so that the bases are all the same. • Take the logarithm of both sides.

  4. Helpful Hint When you use a rounded number in a check, the result will not be exact, but it should be reasonable.

  5. Example 1A: Solving Exponential Equations Solve and check. 98 – x = 27x – 3 Rewrite each side with the same base; 9 and 27 are powers of 3. (32)8 – x = (33)x – 3 To raise a power to a power, multiply exponents. 316– 2x = 33x – 9 16 – 2x = 3x – 9 Bases are the same, so the exponents must be equal. x = 5 Solve for x.

  6. log5 log5 x–1 = log4 log4 x = 1 + ≈ 2.161 Example 1B: Solving Exponential Equations Solve and check. 4x – 1= 5 5 is not a power of 4, so take the log of both sides. log 4x – 1 = log 5 (x– 1)log 4 = log 5 Apply the Power Property of Logarithms. Divide both sides by log 4. CheckUse a calculator. The solution is x ≈ 2.161.

  7. Check It Out! Example 1a Solve and check. 32x = 27 Rewrite each side with the same base; 3 and 27 are powers of 3. (3)2x = (3)3 To raise a power to a power, multiply exponents. 32x = 33 2x = 3 Bases are the same, so the exponents must be equal. x = 1.5 Solve for x.

  8. log21 log21 –x = log7 log7 x = – ≈ –1.565 Check It Out! Example 1b Solve and check. 7–x = 21 21 is not a power of 7, so take the log of both sides. log 7–x = log 21 Apply the Power Property of Logarithms. (–x)log 7 = log 21 Divide both sides by log 7.

  9. log15 3x = log2 Check It Out! Example 1c Solve and check. 23x = 15 15 is not a power of 2, so take the log of both sides. log23x = log15 Apply the Power Property of Logarithms. (3x)log 2 = log15 Divide both sides by log 2, then divide both sides by 3. x ≈ 1.302

  10. 1 7 6 12 2x – 1= x= Example 3A: Solving Logarithmic Equations Solve. log6(2x – 1) = –1 6log6 (2x –1) = 6–1 Use 6 as the base for both sides. Use inverse properties to remove 6 to the log base 6. Simplify.

  11. 100 100 x + 1 x + 1 log4( ) = 1 ( ) 100 x + 1 4log4 = 41 = 4 Example 3B: Solving Logarithmic Equations Solve. log4100 – log4(x + 1) = 1 Write as a quotient. Use 4 as the base for both sides. Use inverse properties on the left side. x= 24

  12. Example 3C: Solving Logarithmic Equations Solve. log5x 4 = 8 4log5x = 8 Power Property of Logarithms. log5x = 2 Divide both sides by 4 to isolate log5x. x = 52 Definition of a logarithm. x= 25

  13. log12x(x +1) 12 = 121 Example 3D: Solving Logarithmic Equations Solve. log12x+ log12(x + 1) = 1 Product Property of Logarithms. log12x(x + 1) = 1 Exponential form. x(x + 1) = 12 Use the inverse properties.

  14. Example 3 Continued x2 + x – 12 = 0 Multiply and collect terms. (x – 3)(x+ 4) = 0 Factor. Set each of the factors equal to zero. x – 3 = 0 or x+ 4 = 0 x = 3 or x= –4 Solve. Check Check both solutions in the original equation. log12x+ log12(x +1) = 1 log12x+ log12(x +1) = 1 x log123+ log12(3 + 1) 1 log12( –4) + log12(–4 +1) 1 log123 + log124 1 log12( –4) is undefined. log1212 1 1 1  The solution is x = 3.

  15. Check It Out! Example 3a Solve. 3 = log 8 + 3log x 3 = log 8 + 3log x 3 = log 8 + log x3 Power Property of Logarithms. 3 = log (8x3) Product Property of Logarithms. 103 = 10log (8x3) Use 10 as the base for both sides. 1000 = 8x3 Use inverse properties on the right side. 125 = x3 5 = x

  16. x 4 2log() = 0 x 4 x 4 2(10log ) = 100 2( ) = 1 Check It Out! Example 3b Solve. 2log x– log 4 = 0 Write as a quotient. Use 10 as the base for both sides. Use inverse properties on the left side. x= 2

  17. Example 4A: Using Tables and Graphs to Solve Exponential and Logarithmic Equations and Inequalities Use a table and graph to solve 2x + 1 > 8192x. Use a graphing calculator. Enter 2^(x + 1)as Y1 and8192xas Y2. In the graph, find the x-value at the point of intersection. In the table, find the x-values where Y1 is greater than Y2. The solution set is {x | x > 16}.

  18. 5 x = 3 Lesson Quiz: Part I Solve. 1. 43x–1 = 8x+1 x ≈ 1.86 2. 32x–1 =20 x = 68 3. log7(5x + 3) = 3 4. log(3x + 1) – log 4 = 2 x = 133 5. log4(x – 1) + log4(3x – 1) = 2 x = 3

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