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Name the angle in four ways. Use the  symbol.

Name the angle in four ways. Use the  symbol. P. 3. R. Q. PQR, RQP, 3, Q. See solution. Given : m1 = 17 Find: m2. 1. 2. m2 = 163. See solution. Find m Boxing. mBoxing = 25.2. See solution. Given : mSQR = 22, mPQR = 144 Find: mPQS. S. P. R. Q.

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Name the angle in four ways. Use the  symbol.

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  1. Name the angle in four ways. Use the  symbol. P 3 R Q PQR, RQP, 3, Q

  2. See solution Given: m1 = 17 Find: m2 1 2 m2 = 163

  3. See solution Find mBoxing. mBoxing = 25.2

  4. See solution Given: mSQR = 22, mPQR = 144 Find: mPQS S P R Q mPQS = 122

  5. Identify the type of angle: Obtuse

  6. True or False: and are a pair of skew lines B A D C FALSE

  7. See solution How many students voted baseball as their favorite sport? 55 students

  8. See solution Given: mAOC = 137, mBOC = 98 Find: mBOD C D B O A mBOD = 141

  9. See solution Given: m1 = 27, m2 = 41 Find: mLON L M 2 1 O N mLON = 68

  10. See solution Given: a right angle Solve for x 22 5x – 2 x = 14

  11. GIVEN: mAOB = 48º, mCOD = 55º, and mAOD = 127º If mAOC = 5x + 7, solve for x. B C A D x = 13 O

  12. GIVEN: mAOB = 48º, mCOD = 55º, and mAOD = 127º If mAOC = 5x + 7, solve for x. 48 + 55 = 103 127 – 103 = 24 mAOC = 72º B 24 C 72 = 5x + 7 A 127 48 55 D x = 13 O

  13. The End

  14. Back Given: m1 = 17 Find: m2 180 - straight line 17 1 2 m2 = 180 – 17 = 163 or x + 17 = 180

  15. Back Find mBoxing. “7% of the circle” multiply mBoxing = .07(360) = 25.2

  16. Back Given: mSQR = 22, mPQR = 144 Find: mPQS S P 144 22 R Q x + 22 = 144 mPQS = 144 – 22 = 122 or

  17. Back How many students voted baseball as their favorite sport? 11% of 500 people = .11(500) = 55 students

  18. Back Given: mAOC = 137, mBOC = 98 Find: mBOD C 98 180 – 137 = 43 137 D B O A mBOD = mBOC + mCOD = 98 + 43 = 141

  19. Back Given: m1 = 27, m2 = 41 Find: mLON L M 41 2 1 27 O N mLON = m1 + m2 = 27 + 41 = 68

  20. Given: a right angle Solve for x The End 22 5x – 2 22 + 5x – 2 = 90 or 5x – 2 = 68 5x + 20 = 90 + 2 + 2 5x = 70  20  20 5x = 70 5 5 x = 14 5 5

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